1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
serious [3.7K]
3 years ago
14

a nuclide of 64/29 cu absorbs a positron. witch is the resulting atom? (A) 65/29Cu (B) 63/29 CU (C) 64/28Ni (D) 64/30 Zn

Chemistry
1 answer:
Nesterboy [21]3 years ago
4 0

Answer : Option D) Zn^{64}_{30}

Explanation : When a positron is getting absorbed it means it will be e^{+1}_{0} so, the Cu^{64}_{29} will get converted;

So, the whole reaction will be;

Cu^{64}_{29} + e^{+1}_{0} ----> Zn^{64}_{30}.

This will convert the whole element of Cu will get changed into Zn. As, it absorbs by the positron, the atomic number gets increased from 29 to 30.

You might be interested in
WHICH OF THE FOLLOWING WOULD NOT BE AN EXAMPLE OF AN OBJECT ACCELERATING?
Marrrta [24]
A would be the correct answer hopefully this helps
5 0
3 years ago
In your double replacement reaction, the more reactive metal "pushed" the other one out of its place. Without using the Internet
irakobra [83]
You are using the internet right now. The question told you not to. Lol
5 0
3 years ago
When 412.5g of calcium carbonate react with 521.9g of aluminum fluoride,how many grams of each product can be produced
aliya0001 [1]
<h3><u>Answer;</u></h3>

321.8 g CaF2

321.5 g Al2(CO3)3

<h3><u>Explanation;</u></h3>

The equation for the reaction is;  

3 CaCO3 + 2 AlF3 → 3 CaF2 + Al2(CO3)3  

Number of moles of CaCO3 will be;

=(412.5 g CaCO3) / (100.0875 g CaCO3/mol)

= 4.12139 mol CaCO3  

Number of moles of AlF3 will be;

= (521.9 g AlF3) / ( 83.9767 g AlF3/mol)

= 6.21482 mol AlF3

But;

4.12139 moles of CaCO3 would react completely with 4.12139 x (2/3) = 2.74759 moles of AlF3.

Thus; there is more AlF3 present than that, so AlF3 is in excess, and CaCO3 is the limiting reactant.  

Therefore;

Mass of CaF2 will be;

(4.12139 mol CaCO3) x (3/3) x (78.0752 g CaF2/mol) = 321.8 g CaF2  

Mass of Al2(CO3)3 on the other hand will be;

(4.12139 mol CaCO3) x (1/3) x (233.9903 g Al2(CO3)3/mol) = 321.5 g Al2(CO3)3

3 0
4 years ago
One of the waste byproducts of a nuclear reactor using uranium-235 is strontium-90 with half-life of about 28 years. If we have
e-lub [12.9K]

Answer:

(a) 140 years

(b) 3.125 pounds

Explanation:

<u>QuestIons</u>

(a) How long is five half-life

(b)  How much radioactive strontium is left after five half-life

Given that:

Half-life is about 28 years; &

There are 100 pounds of this radioactive waste

Five half-life will be;

= 28 × 5

= 140 years

The amount of radioactive remaining after five half-life is:

= 100 \times( \dfrac{1}{2}) ^5

= 100 × 0.03125

= 3.125 pounds

5 0
3 years ago
Mixture's and solutions
Anastaziya [24]

Mixtures and solutions... what?

8 0
3 years ago
Other questions:
  • How many atoms of aluminum (Al) are in 2.15 mol of aluminum? answer in units of atoms.
    6·2 answers
  • A 0.420 M Ca(OH)2 solution was prepared by dissolving 64.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol
    12·2 answers
  • What is the pH of a solution with a hydrogen-ion concentration of 4.2 x 10-10<br> M?
    14·1 answer
  • The motion that occurs because the star is moving towards or away from the earth is known as
    8·2 answers
  • Dinitrogen trisulfide symbol
    12·2 answers
  • How would you describe a particle of alpha radiation?
    14·1 answer
  • Summarize the overall trend observed for ionization energy.
    14·2 answers
  • Match the definitions on the left with the terms on the right.
    13·2 answers
  • How many molecules are there in 18.5 moles of water
    9·1 answer
  • What pressure is required to compress 196.0 liters of air at 1.83 atmosphere into a cylinder whose volume is 26.0 liters
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!