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serious [3.7K]
3 years ago
14

a nuclide of 64/29 cu absorbs a positron. witch is the resulting atom? (A) 65/29Cu (B) 63/29 CU (C) 64/28Ni (D) 64/30 Zn

Chemistry
1 answer:
Nesterboy [21]3 years ago
4 0

Answer : Option D) Zn^{64}_{30}

Explanation : When a positron is getting absorbed it means it will be e^{+1}_{0} so, the Cu^{64}_{29} will get converted;

So, the whole reaction will be;

Cu^{64}_{29} + e^{+1}_{0} ----> Zn^{64}_{30}.

This will convert the whole element of Cu will get changed into Zn. As, it absorbs by the positron, the atomic number gets increased from 29 to 30.

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Answer:

See explaination

Explanation:

1)

we know that

half cell with higher reduction potential is cathode

so

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anode :

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so

overall reaction is

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now

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so

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now

in this case

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reducing agents are Cr and N2

higher the reduction potential , stronger the oxidizing agent

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so

oxidzing agents

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reducing agents

Cr > N2

2)

cathode :

Au+ + e- --> Au

anode :

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overall reaction

3Au+ + Cr ---> 3Au + Cr+3

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Eo cell = 2.43

now

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reducing agents :

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3)

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andoe :

Au ---> Au+ + e-

overall

2 Au + N20 + 2H+ --> 2 Au+ + N2 + H20

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Eo cell = 0.08

oxidizing agents

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Explanation:

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