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3 years ago

Which of the following is not an example of a subatomic particle? electron photon neutron proton

Chemistry

2 answers:

asambeis [7]3 years ago

5 0

I'm pretty sure all 4 are subatomic particles but if i had to guess i'd be Photons

JulijaS [17]3 years ago

3 0

The correct answer is a photon.

A photon refers to a particle signifying a quantum of light or other electromagnetic radiation. A photon carries energy equivalent to the radiation frequency, however, exhibits zero rest mass.

A subatomic particle refers to a unit of energy or matter, that is, the basic makeup of all the matter. On the basis of modern atomic theory, an atom exhibits a nucleus, also known as the core or its center. The nucleus comprises subatomic particles, that is, neutrons and protons. The neutrons are neutral particles, and the protons are positively-charged particles. A cloud of very small subatomic particles known as electrons surrounds the nucleus. The electrons are negatively charged particles.

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Lactose is a disaccharide (two monosaccharides joined together). to metabolize lactose, individuals require an enzyme known as l

Andrei [34K]

The answer is the reaction hydrolyzes the sugar.

Lactose is a disaccharide (two monosaccharides joined together). To metabolize lactose, individuals require an enzyme known as lactase.

Lactose is a disaccharide that is made from glucose and galactose. To metabolize lactose, individuals require an enzyme known as lactase.

The reaction hydrolyzes the sugar.

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4 years ago

How many atoms of hydrogens are found in 3.21 mol of<br>C3H8?

damaskus [11]

Answer:

1.55 × 10²⁵ atoms of H

Explanation:

3.21mol C₃H₈ × 8mol H × (6.022×10²³)

8 0

3 years ago

Which state of matter has a definite volume and takes the shape of its container?

DedPeter [7]

The answer is - liquid

6 0

3 years ago

A voltaic cell made of a Cr electrode in a solution of 1.0 M in Cr3+ and a gold electrode in a solution that is 1.0 M in Au3+.

Vikki [24]

Answer: a) Anode: $Cr\rightarrow Cr^{3+}+3e^-$

Cathode: $Au{3+}+3e^-\rightarrow Au$

b) Anode : Cr

Cathode : Au

c) $Au^{3+}+Cr\rightarrow Au+Cr^{3+}$

d) $E_{cell}=2.14V$

Explanation: -

a) The element Cr with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element Au with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.

At cathode: $Au{3+}+3e^-\rightarrow Au$

At anode: $Cr\rightarrow Cr^{3+}+3e^-$

b) At cathode which is a positive terminal, reduction occurs which is gain of electrons.

At anode which is a negative terminal, oxidation occurs which is loss of electrons.

Gold acts as cathode ad Chromium acts as anode.

c) Overall balanced equation:

At cathode: $Au{3+}+3e^-\rightarrow Au$ (1)

At anode: $Cr\rightarrow Cr^{3+}+3e^-$ (2)

Adding (1) and (2)

$Au^{3+}+Cr\rightarrow Au+Cr^{3+}$

d) $E^0_(Cr^{3+}/Cr)$ = -0.74 V