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3 years ago

Which of the following is not an example of a subatomic particle? electron photon neutron proton

Chemistry

2 answers:

asambeis [7]3 years ago

5 0

I'm pretty sure all 4 are subatomic particles but if i had to guess i'd be Photons

JulijaS [17]3 years ago

3 0

The correct answer is a photon.

A photon refers to a particle signifying a quantum of light or other electromagnetic radiation. A photon carries energy equivalent to the radiation frequency, however, exhibits zero rest mass.

A subatomic particle refers to a unit of energy or matter, that is, the basic makeup of all the matter. On the basis of modern atomic theory, an atom exhibits a nucleus, also known as the core or its center. The nucleus comprises subatomic particles, that is, neutrons and protons. The neutrons are neutral particles, and the protons are positively-charged particles. A cloud of very small subatomic particles known as electrons surrounds the nucleus. The electrons are negatively charged particles.

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Read the given expression. X = number of protons − number of core electrons Which of the following explains the identity of X an

shepuryov [24]

Answer: The correct statement is X is the effective nuclear charge, and it increases across a period.

Explanation:

We are given that:

X = number of protons − number of core electrons

Effective nuclear charge is defined as the actual nuclear charge (Z = number of protons) minus the screening effect caused by the electrons present between nucleus and valence electrons. These electrons are the core electrons.

The formula used for the calculation of effective nuclear charge given by Slater is:

$Z^*=Z-\sigma$

where,

$Z^*$ = effective nuclear charge

Z = atomic number or actual nuclear charge or number of protons

$\sigma$ = Screening constant

The effective nuclear charge increases as we go from left to right in a period because nuclear charge increases with no effective increase in screening constant.

Hence, the correct answer is X is the effective nuclear charge, and it increases across a period.

5 0

3 years ago

What is the concentration of a solution containing 1.11 g sugar (sucrose, C12H22O11, MW = 342.3 g/mol, d = 1.587 g/cm3) in 432 m

djyliett [7]

Answer:

0.0075 M

0.0060 m

Explanation:

Our strategy here is to use the definition of molarity and molality to solve this question.

The molarity is the number of moles of solute, sucrose in this case, per liter of solution.

The molality is the number of moles of solute per kilogram of solvent.

So the molarity of the solution is

M = moles of solute/ V solution

As we see we need the volume of solution since we are only given the volume of solvent, but this will be easy to compute since we have the density of sucrose.

So determine the moles of sucrose , and the volume of solution:

Moles sucrose = 1.11 g/342.3 g/mol = 3.24 x 10⁻³ M

Volume of solution = Vol Sucrose + Vol glycerine

d = m/V ⇒ Vsucrose = m / d = 1.11 g/ 1.587 g/cm³ = 0.70 cm³

Vol solution = 432 mL + 0.70 mL = 432.7 mL (1cm³ = 1 mL)

Vol solution = 432.7 mL x 1 L / 1000 mL = 0.4327 L

⇒ M = 3.2 x 10⁻³ mol / 0.4327 L = 0.0075 M

For the molarity what we need is to first calculate the kilograms of glycerine from the given density:

d = m/v ⇒ m = d x v = 1.261 g/cm³ x 432 cm³ = 544.75 g

Converting to Kg:

544.75 g x 1 Kg/ 1000 g = 0.544 kg

Now the molality is

m = mol sucrose/ kg solvent = 3.24 x 10⁻³ mol / 0.544 Kg = 0.0060 m

Note: In the calculation for volume of solution we could have approximated it to that of just glycerine, but since the density of sucrose was given we calculated the total volume of solution to be more rigorous.

8 0

3 years ago