By definition, the arc length is given by:
arc = R * theta * ((2 * pi) / 360)
Where,
theta: angle in degrees
R: radio
We have then:
(Arc) QPT if <QZT = 120:
theta = 360-120 = 240 degrees
R = 13.5 units
Substituting values we have:
(Arc) QPT = R * theta * ((2 * pi) / 360)
(Arc) QPT = (13.5) * (240) * ((2 * pi) / 360)
(Arc) QPT = 56.55 units
Answer:
(Arc) QPT = 56.55 units
Answer:
113`F= 46.11° Celsius
Step-by-step explanation:
(Celsius°C × 9/5) + 32 = Fahrenheit
(Celsius°C × 9/5) + 32 = 113
(Celsius°C × 9/5) = 113 - 32
(Celsius°C × 9/5) = 83
Celsius = 5(83)/9
Celsius = 46.11° Celsius
X = -8.
subtract 19.
-X = 8
divide by -1.
X = -8
42n, you can't take the "n" away. The "n" means times a number, so I I write n=2, then the expression will be 42 x 2, substitute the n with a 2