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e-lub [12.9K]
3 years ago
8

Deanna is adjusting a satellite because she finds it is not focusing the incoming radio waves perfectly. The shape of her satell

ite can be modeled by x^2=12y where x and y are modeled in inches. She realizes that the static is a result of the feed antenna shifting slightly off the focus point. What is the focus point of the satellite?

Mathematics
2 answers:
pychu [463]3 years ago
4 0
Hello,
Please, see the attaced file.
Thanks.

Brums [2.3K]3 years ago
3 0

Answer:

The shape of satellite which is in the shape of parabola, opening upwards is, x^2=12 y, having vertex (0,0).

Comparing with general equation of parabola

x^2=4 a y , having vertex (0,0) and focus (0,a).

Comparing the two above equation of parabola

4 a y = 12 y

4 a = 12

a=3

So, focus of the satellite which is in the shape of parabola=(0,3)

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Ella has 0.5 lbs of sugar. How much water should she add to make the following concentrations? Tell Ella how much syrup she will
Oksanka [162]

Answer:

Ella should add 32\dfrac{5}{6} lbs of water.

Total weight of syrup 33\dfrac{1}{3} lbs

Step-by-step explanation:

Weight:

Weight of sugar = 0.5 lbs.

Weight of water added = x lbs

Total weight = 0.5 + x lbs

Percentage:

0.5 + x  --  100%

0.5  --  1.5%

Write a proportion:

\dfrac{0.5+x}{0.5}=\dfrac{100}{1.5}

Cross multiply:

1.5(0.5+x)=0.5\cdot 100\\ \\0.75+1.5x=50\\ \\1.5x=50-0.75\\ \\1.5x=49.25\\ \\x=\dfrac{49.25}{1.5}=\dfrac{4,925}{150}=\dfrac{197}{6}=32 \dfrac{5}{6}\ lbs

Ella should add 32\dfrac{5}{6} lbs of water.

Total weight of syrup

32\dfrac{5}{6}+\dfrac{1}{2}=32\dfrac{5}{6}+\dfrac{3}{6}=33\dfrac{1}{3}\ lbs

3 0
3 years ago
Question is attached.
Gemiola [76]
1. c
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3. a
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4 0
3 years ago
Which is the best way to find the
Vesnalui [34]

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C. Elimination, because - 2y and 2y are opposites.

Step-by-step explanation:

5 0
3 years ago
Sasha found the product of 1/8 x 40 to be 5. Use that information to find the product of 7/8 x 40 for
ANEK [815]
The answer is 35.

7/8 x 40 = 280/8 = 35
3 0
3 years ago
Read 2 more answers
M=-4/3, point (0,-12)
postnew [5]
Y - y1 = m(x - x1)
slope(m) = -4/3
(0,-12)....x1 = 0 and y1 = -12
sub
y - (-12) = -4/3(x - 0) =
y + 12 = -4/3(x - 0) <=== point slope form

y + 12 = -4/3x 
y = -4/3x - 12 <=== slope intercept form

y = -4/3x - 12
4/3x + y = -12
4x + 3y = -36 <=== standard form
3 0
3 years ago
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