Question

80 points! pls help! Recall that the equation for horizontal distance h in feet of a projectile with initial velocity v0 and initial angle θ is given by h = v^2/16sin0cos0

Answer 1

Answer:

a) 0.6435 radians

b) 80.1 feet/sec

Step-by-step explanation:

a) 75 = (50²/16)sin(theta)cos(theta)

sin(theta)cos(theta) = 0.48

2sin(theta)cos(theta) = 0.96

sin(2theta) = 0.96

2theta = 1.287002218

Theta = 0.6435011088 radians

b) 200 = (v²/16)sin(0.75)cos(0.75)

6416.072347 = v²

v = 80.10038918 feet/sec