If the current temperature is -11°F, what change in temperature would result in a final temperature of -27°F?

3.8n - 13 = 1.4n + 5

Eddi Din [679]

Answer: N = 7.5

Step-by-step explanation:

6 0

3 years ago

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to make 5 apple pies you need about 2 pounds of apples how many pounds of apples do you need to make 20 apple pies

myrzilka [38]

About eight pounds.

You divide 20 by 5, which is four. You then multiply 4 by the amount of pounds (2).

Hope that helps

5 0

4 years ago

ANOTHER 20 POINTS

Mnenie [13.5K]

Answer:

$960

Step-by-step explanation:

1/5= .2

1-0.2= 0.8

1200×0.8= 960

7 0

3 years ago

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Test the null hypothesis Upper H 0 : (mu 1 minus mu 2 )equals 0H0: μ1−μ2=0 versus the alternative hypothesis Upper H Subscript a

Law Incorporation [45]

Answer:

The test statistic t is t=2.9037.

The null hypothesis is rejected.

For a significance level of 0.05, there is enough evidence to support the alternative hypothesis.

Step-by-step explanation:

The question is incomplete:

The sample 1, of size n1=25 has a mean of 1.15 and a standard deviation of 0.31.

The sample 2, of size n2=25 has a mean of 0.95 and a standard deviation of 0.15.

This is a hypothesis test for the difference between populations means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

The significance level is α=0.05.

The difference between sample means is Md=0.2.

$M_d=M_1-M_2=1.15-0.95=0.2$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{0.31^2+0.15^2}{25}}\\\\\\s_{M_d}=\sqrt{\dfrac{0.119}{25}}=\sqrt{0.005}=0.069$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.2-0}{0.069}=\dfrac{0.2}{0.069}=2.9037$

The degrees of freedom for this test are:

$df=n_1+n_2-1=25+25-2=48$

This test is a two-tailed test, with 48 degrees of freedom and t=2.9037, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t>2.9037)=0.0056$

As the P-value (0.0056) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

8 0

4 years ago

Gisselle has 1/2 of a candy bar. She role off 1/2 of what she had. She then took the piece she broke off and split it into three

saul85 [17]

Answer:

$\frac{1}{12}$

Step-by-step explanation:

Given:

Gisselle has 1/2 of a candy bar.

She role off 1/2 of what she had and split it into three equal pieces.

Question asked:

What fraction of a candy bar was each piece?

Solution:

Gisselle has = $\frac{1}{2} \ of \ a \ candy \ bar$

She role off = $\frac{1}{2} \ of \ what\ she \ had$

$=\frac{1}{2} \ of\ \frac{1}{2}\\=\frac{1}{2} \times \frac{1}{2}\\\\=\frac{1}{4}$

As she split it into three equal pieces, we will divided it by 3, we get,

$\frac{1}{4} \div3\\\frac{1}{4}\times\frac{1}{3}$

$\frac{1}{12}$

Therefore, fraction of a candy bar of each piece is $\frac{1}{12}$

4 0

3 years ago