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3 years ago

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There are 90 girls and 60 boys in the sixth grade at a middle school. Of these students, 9 girls and 3 boys write left-handed. W

hat percentage of the sixth graders at this middle school write left handed?

1 answer:

Juliette [100K]3 years ago

6 0

.08% 90+60=150 and 9+3=12 12/150=.08

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Frank started an assignment at 6:26 PM and finished it at 7:44 PM. How long did it take him? Give your answer in minutes.

Svet_ta [14]

7.44-6.26=1.18
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2 years ago

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Solve x;<br> x- 2 (divided by) -8 = 0<br><br> --Please Help! Due in for tomorrow! Xx

Yanka [14]

X=2
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3 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

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3 years ago

Hello pls help me answer this correctly!!

anygoal [31]

Answer:

A - 23

B - Finn and 16

Step-by-step explanation:

Counting each box until you get to C gives you 23 and 16 from points A and B

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=3x%20%7B%20%7D%5E%7B2%7D%20%20%3D%20%20-%2054%20" id="TexFormula1" title="3x { }^{2} = - 54

valkas [14]

Answer:

No real solutions

Step-by-step explanation:

Divide both sides by 3

3x^3/3=-54/3

x^2=-18

Take square root

x=±√−18

4 0

3 years ago