Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer
To find the Area you need to use the formula L x W!! Anyways, You have to multiply the Length x the width. Your Length is 1 3/4 and your width is 1 1/2. So 1 3/4 x 1 1/2 is 2 5/8!!
Answer:
its 11/6
Step-by-step explanation:
GCD of 11 and 6 is 1
Divide both the numerator and denominator by the GCD
11 ÷ 1
6 ÷ 1
Reduced fraction:
11/6
Answer:
The correct answer to the question is;
1 < x < <u>4</u>
Step-by-step explanation:
The give parameters are;
ΔABC is an isosceles triangle, with the vertex angle = 35° + 20° = 55°
Therefore, the two base angles are 62.5° each by definition of isosceles triangle
Given that the angle subtended by 4·x - 4 which is 25° is lesser than the angle subtended by the 12 unit side length which is 35° we have;
4·x - 4 < 12
4·x < 12 + 4
∴ 4·x < 16
x < 16/4
x < 4
Therefore, the range is 1 < x < 4
Answer:
N(20) = T
Step-by-step explanation:
N = Amount of lawns
20 = payment per lawn
T= payment after N lawns
Lets say there were 2 lawns
2(20)=T
40$ for 2 lawns
