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3 years ago

(6a −? )5a =? a2 − 35a

2 answers:

7 0

Answer:
5a(6a-7) = 30a² - 35a

Explanation:
Before we begin, remember the following:
a(b+c) = ab + bc

Now for the given:
Assume that the first question mark is x and that the second question mark is y.

The expression now becomes:
(6a-x) * 5a = ya² - 35a
Distribute the 5a over the bracket and equate it with the right-hand side as follows:
5a(6a) - 5a(x) = ya² - 35a
30a² - 5ax = ya² - 35a

By comparison:
30a² = ya² ..............> This means that y = 30
-5ax = -35a
-5x = -35
5x = 35
x = 35/5
x = 7

Based on the above, the expression is:
5a * (6a-7) = 30a² - 35a

Hope this helps :)

timofeeve [1]3 years ago

5 0

(6a - 7)5a = 30a^2 - 35a

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Shannon is selling boxes cookies and candy for a fundraiser. She's sold each box of cookies for $5.25. She also sold one one box

defon

Answer:

The minimum boxes of cookies is 39

Step-by-step explanation:

Let

x ----> the number of boxes of cookies sold

y ----> the number of boxes of candies sold

we know that

The word "at least" means "greater than or equal to"

The inequality that represent this problem is

$5.25x+8.75y\geq 200$

The solution is the shaded area above the solid line $5.25x+8.75y=200$

using a graphing tool

The solution is the shaded area -----> see the attached figure

Find out the minimum boxes of cookies needed to sell to reach the goal

assuming only cookies are sold

For y=0

$5.25x+8.75(0)\geq 200$

$5.25x\geq 200$

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Round up

therefore

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5 0

3 years ago

Please help!!!!!!!!!!!!!!!!!!!!!!!!!! answer both

weeeeeb [17]

Solution 1 :-

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We know that, $a^{\frac{m}{n}} = \sqrt[n]{a^m}$

Therefore , this can be written as ,

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Solution 2:-

Given expression ,

$\implies \sqrt[3]{24^{10}}$

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2 years ago

Read 2 more answers

Factor this equation 4x^2+12x-7

Levart [38]

$4x^2+12x-7=0\\\\a=4;\ b=12;\ c=-7\\\Delta=b^2-4ac\\\\\Delta=12^2-4\cdot4\cdot(-7)=144+112=256 \ \textgreater \ 0\\\\therefore\\x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{256}=16\\\\x_1=\dfrac{-12-16}{2\cdot4}=\dfrac{-28}{8}=\boxed{-\dfrac{7}{2}}\\\\x_2=\dfrac{-12+16}{2\cdot4}=\dfrac{4}{8}=\boxed{\dfrac{1}{2}}$