you went to move a 41 kg bookcase to a different place in the living room. if you push with a force of 65 N and the bookcase acc
1 answer:
0.15
Explanation:
Given parameters:
Mass of bookcase = 41kg
Force applied = 65N
Acceleration = 0.12m/s²
Unknown:
Coefficient of kinetic friction between the bookcase and carpet = ?
Solution:
To solve this problem, the forces acting on the bookcase are;
frictional force
net force
applied force
weight
F - f = ma in the horizontal direction ----- i
F is the applied force
f is frictional force
m is the mass
a is the acceleration
ma is the net force
In the vertical axis:
R = mg
R is the normal reaction
mg is the weight of the body
f = μN = μmg , put into equation i
F - μmg = ma
μ is the coefficient of friction
input the variables;
65 - μ(41 x 9.8) = 41 x 0.12
65 - 401.8μ = 4.92
- 401.8μ = 4.92 - 65
- 401.8μ = -60.1
μ = = 0.15
learn more:
Friction brainly.com/question/6443626
#learnwithBrainly
You might be interested in
Answer:
<h2>a) 2.5 s</h2><h2>b) 1.55 m</h2><h2 />Explanation:
<h3>Given :-</h3><h2>Completes 2 oscillation in 5s.</h2><h2>A) Time period = ?</h2><h2 /><h2><em>Thus 1 oscillation is completed in 2.5 </em><em>s.</em>
<h2>B) If g = 9.8 ms−², find its length.</h2><h2>Thus the length of g = 9.8 ms −² = 1.55m
<h2>Hope it helps u.......</h2><h2>STAY SAFE, STAY HEALTHY AND BLESSED .</h2><h2> HAVE A MARVELOUS DAY AHEAD !</h2><h2>THANK YOU !</h2>