Question

you went to move a 41 kg bookcase to a different place in the living room. if you push with a force of 65 N and the bookcase accelerates at 0.12 m/s2 what is the coefficient of kinetic friction between the bookcase and the carpet?

Answer 1

0.15

Explanation:

Given parameters:

Mass of bookcase = 41kg

Force applied = 65N

Acceleration = 0.12m/s²

Unknown:

Coefficient of kinetic friction between the bookcase and carpet = ?

Solution:

To solve this problem, the forces acting on the bookcase are;

frictional force

 net force

  applied force

  weight

 F - f$_{r}$ = ma   in the horizontal direction ----- i

F is the applied force

f$_{r}$ is frictional force

m is the mass

 a is the acceleration

ma is the net force

In the vertical axis:

 R = mg

R is the normal reaction

 mg is the weight of the body

f$_{r}$ = μN = μmg , put into equation i

F - μmg  = ma

μ is the coefficient of friction

input the variables;

 65 - μ(41 x 9.8) = 41 x 0.12

65 - 401.8μ = 4.92

  - 401.8μ  = 4.92 - 65

  - 401.8μ  = -60.1

       μ = $\frac{60.1}{401.8}$ = 0.15

 

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Friction brainly.com/question/6443626

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