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kap26 [50]
2 years ago
14

The resistance between 2 points in an electrical circuit is 1.1 Ω. What additional resistance

Physics
1 answer:
valentinak56 [21]2 years ago
5 0

Answer:

the new resister is 11 ohms.

Explanation:

Set it  up like this.

1/x + 1/1.1 = 1                    Subtract 1/1.1 from both sides

1/x = 1 - 1/1.1

1 - 1/1.1 = 1/11

1/x = 1/11                          Cross multiply

11 = x

If 1/11 bothers you, you could do it it another way.

1 - 1/1.1 = (1.1 - 1 ) / 1.1 = 0.1 / 1.1  Multiply top and bottom by 10

0.1*10/(1.1 * 10 ) = 1 / 11

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guaranteeing freedom of speech, press, assembly, and exercise of religion

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2 years ago
5 What is the angular displacement at the end of the 25-mm-diameter shaft and the linear displacement of point A of Figure P5.5
Anvisha [2.4K]

5 What is the angular displacement at the end of the 25-mm-diameter shaft and the linear displacement of point A of Figure P5.5

<h3>What is displacement ?</h3>

A displacement is a vector in geometry and mechanics that has a length equal to the shortest distance between a point P's initial and final positions. It calculates the length and angle of the net motion, or total motion, in a straight line from the starting point to the destination of the point trajectory. The translation that links the starting point and the ending point can be used to spot a displacement.

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brainly.com/question/321442

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3 0
1 year ago
A locomotive engine pulls a train with a constant force comment on whether its acceleration will increase or decrease if more co
julia-pushkina [17]

Explanation:

the acceleration will be unchanged according to newton second law of motion

7 0
3 years ago
Convert 6.6 meters to centimeters
Lina20 [59]

Answer:

660 centimeters

Explanation:

There are 100 cm in 1 m. To convert from m to cm, multiply by 100.

6.6 \times 100 = 660

There are 660 cm in 1 m.

6 0
3 years ago
Read 2 more answers
A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a rope that goes over an ideal pulley. If the masses are
irga5000 [103]

Answer:

The time taken will be 0.553 seconds.

Explanation:

We should start off by finding the force exerted by the rope on the 3kg weight in this case.

Weight of 5kg mass = 5 * 9.81 = 49.05 N

Weight of 3kg mass = 3 * 9.81 = 29.43 N

The force acting upward on the 3kg mass will equal the weight of the 5kg mass. Thus the resultant force acting on the 3kg mass is:

Total force = 49.05 - 29.43 = 19.62 N (upwards)

We can now find the acceleration:

F = m * a

19.62 = 3 * a

a = 6.54 m/s^2

We now use the following equation of motion to get the time taken to travel 1 meter:

s=u*t+\frac{1}{2} (a*t^2)

1=0*t+\frac{1}{2} (6.54*t^2)

t = 0.553 seconds

4 0
3 years ago
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