Answer:
friction
Explanation:
carpet floor creates for friction
Answer:
1. Newton's First Law of Motion
2.Newton's Third Law of Motion
3.Newton's Third Law of Motion
4.Newton's Second Law of Motion
5.Newton's Third Law of Motion
6.Newton's Second Law of Motion
7.Newton's First Law of Motion
Explanation:
Newton's First Law of Motion states that an object remain at rest or moving with a uniform velocity unless an external force acts on it. This is the law of inertia
Newton's Second Law of Motion states that the force of an objects is the product of mass and acceleration.
Newton's Third Law of Motion states that when two objects interact, a pair of forces act on the objects, and they are equal and act in opposite directions.
6. 0N. This questions requires understanding of how friction functions. Friction is a resistive force, meaning it opposes the direction of any applied or unbalanced forces. The box in the question experiences no horizontal force, so there is no resistive force in response to it, making it 0N.
7. This question tests your understanding of static friction. Static friction only applies when an applied or unbalanced force is applied to an object which does not move. The static friction always equals the magnitude of the applied or unbalanced force component parallel to the surface which the object rests on. The question states that the crate starts to move only when the applied force exceeds 313N, so we use this value to determine the force of static friction. The additional info in the question pertaining to when the crate is moving is irrelevant when determining static friction (only relevant if determining kinetic friction). Knowing this we solve for the weight of the crate:
F = mg
F = (45)(9.8)
F = 441N = Normal Force
The weight of the crate is also equal to the Normal Force since the object rests on a horizontal surface and the applied force is horizontal as well. In this question, since the object is not moving at 313N of applied force, the magnitude of static friction equals the applied force:
Ff = μs * Fn
(313) = μs (441)
0.71 (rounded) = μs
Answer:
w = 0.173 N
Explanation:
The weigh of any object is computed by multiplying its mass to the acceleration of gravity, so we need to find the gravity on that planet in order to compute the weigh we want.
The ball has a mass of 0.1 kg and its released from a height of 10 m, therefore it is in a free fall motion with gravity acting as a constant acceleration on the body, we can use the equations for free fall movement in order to determine the value for this acceleration:
y(t) = v_0 * t + y_0 - 0.5 * g * t^2
y(t) is the position in the end of the movement, when t = 3.4 s, so y(t) = 0 m.
v_0 is the initial velocity, in this case v_0 = 0 m/s.
y_0 is the initial position of the ball, in this case it is 10 m.
g is the gravity that we want to know.
Applying these values in the equation we have:
0 = 0*(3.4) + 10 - 0.5*g*(3.4)^2
0 = 10 - 0.5*11.56*g
0 = 10 -5.78*g
5.78*g = 10
g = 1.73 m/s^2
Then we can use this value to find out the weigh of the ball in that planet:
w = g*m = 0.1*1.73 = 0.173 N
