All categories

3 years ago

Definition for compression and rarefraction

2 answers:

6 0

Compression and rarefaction are two phenomenon occurs in longitudunal wave!

when there is denser particle gathering in that wave , there we called it compression and the rarer part of particles is rarefaction !

inn [45]3 years ago

5 0

Compression is the state of being compressed, or pressed together (forcing into less space)
Rarefaction is the act of becoming less dense.
The two are opposites if that helps.

You might be interested in

A constant net torque is exerted on an object. Which of the following quantities for the object cannot be constant? (Select all

prohojiy [21]

Answer:

A. kinetic energy

B. angular velocity

E. angular position

Explanation:

The quantities that cannot be constant if a constant net torque is exerted on an objecta are:

A. Kinetic energy. If a torque is applied, the linear or angular speed will be changing at a rate proportional to the torque, so the kinetic energy will change too.

B. Angular velocity. It will change at a rate equal to the torque.

C. Angular position. If the angular velocity changes, the angular position will change.

3 0

3 years ago

The direction of the force on a current-carrying wire in a magnetic field is

Bess [88]

Answer:

Explanation:

The forces acting on a conductor carrying current placed in a magnetic field is analysed using the Fleming's left hand rule.

The rule states that "If the fire finger, the middle finger and the thumb are held mutually perpendicular to one another in a magnetic field, the fore finger acts in the direction of the magnetic field, the middle finger acts on the direction of the current while the thumb acts in the direction of the force.

Based on the rule, it can be inferred this current carrying wire placed in the magnetic field acts perpendicular to the magnetic field and force acting on the wire.

6 0

3 years ago

Read 2 more answers

You're using a monochromatic beam of light with wavelength 500 nm in an interferometer. What is the minimum distance you would n

xxTIMURxx [149]

Answer:

The minimum distance moved by mirror is 125 nm

Explanation:

Given:

Wavelength of light $\lambda = 500 \times 10^{-9}$ m

Here given in question, spot of constructive interference change to a destructive interference.

Hence minimum distance moved by one of mirror is given by,

$t = \frac{1}{2}(\frac{\lambda}{2} )$

Where $t =$ distance moved by mirror

$t = \frac{\lambda }{4}$

$t = \frac{500\times 10^{-9} }{4}$

$t = 125 \times 10 ^{-9}$

Therefore, the minimum distance moved by mirror is 125 nm

4 0

3 years ago

A 5.0 cm object is 6.0 cm from a convex lens, which has a focal length of 7.0 cm.

Reil [10]

Answer : The distance of the image from the lens is, -42 cm

The height of the image is, 35 cm

Solution :

First we have to calculate the image distance.

Formula used :

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where,

f = focal length = 7 cm

p = object distance = 6 cm

q = image distance = ?

Now put all the given values in the above formula, we get the distance of the image from the lens.

$\frac{1}{7cm}=\frac{1}{6cm}+\frac{1}{q}$

$q=-42cm$

Therefore, the distance of the image from the lens is, 42 cm and the negative sign indicates that the image is virtual.

Now we have to calculate the height of the image.

Formula used :

$\frac{h}{h'}=\frac{p}{q}$

where,

h = height of object = 5 cm

h' = height of image = ?

Now put all the given values in this formula, we get the height of the image.

$\frac{5cm}{h'}=\frac{6cm}{-42cm}=-35cm$

Therefore, the height of the image is, 35 cm and the negative sign indicates that the image is inverted.

5 0

4 years ago

Read 2 more answers

Find the number of free electrons per cubic centimeter in germanium at room temperature given that there are 5.6x10-10 free elec

charle [14.2K]

Answer:

$2.41 \times 10^{13}\ free\ electrons/cm^3$

Explanation:

given,

free electron per atom = 5.6 x 10⁻¹⁰

density of silicon = 5.32 g/cm³

molar mass of silicon = 72.59 g/mol

number of moles per cubic centimeter

= $\dfrac{5.32}{72.59}\ mole/cm^3$

number of atom per cubic centimeter

= $\dfrac{5.32}{72.59}\times 6.022 \times 10^{23}\ /cm^3$

number of free electron per cubic centimeter

= $\dfrac{5.32}{72.59}\times 6.022 \times 10^{23}\times 5.6 \times 10^{-10}/cm^3$

= $2.41 \times 10^{13}\ free\ electrons/cm^3$

5 0

4 years ago