Answer: W = 0.3853 J, e = 0.052 m
Explanation: Given that,
K =285.0N/M , L = 0.230m , F = 15N , e = ?
F = Ke
15 = 285 × e
e = 15÷ 285
e =0.052 m
e + L = 0.052 + 0.230
= 0.282m ( spring new length )
Work needed to stretch the spring
W = 1/2ke2
W = 1/2 × 285 x 0.052 × 0.052
W = 0.3853 J
Answer: The variable that you manipulate is called the independent variable. The variable that you measure is called the dependent variable.
The charge on the electron is 1.6x10^-19C. So, 10^24 of them will be a charge of 1.6x10^5C, F = q1xq2/[(4pi epsilon nought)r^2]
Answer:
The ratio of T2 to T1 is 1.0
Explanation:
The gravitational force exerted on each sphere by the sun is inversely proporational to the square of the distance between the sun and each of the spheres.
Provided that the two spheres have the same radius r, the pressure of solar radiation too, is inversely proportional to the square of the distance of each sphere from the sun.
Let F₁ and F₂ = gravitational force of the sun on the first and second sphere respectively
P₁ and P₂ = Pressure of solar radiation on the first and second sphere respectively
M = mass of the Sun
m = mass of the spheres, equal masses.
For the first sphere that is distance R from the sun.
F₁ = (GmM/R²)
P₁ = (k/R²)
T₁ = (F₁/P₁) = (GmM/k)
For the second sphere that is at a distance 2R from the sun
F₂ = [GmM/(2R)²] = (GmM/4R²)
P₂ = [k/(2R)²] = (k/4R²)
T₂ = (F₂/P₂) = (GmM/k)
(T₁/T₂) = (GmM/k) ÷ (GmM/k) = 1.0
Hope this Helps!!!
Answer:
I = 0.2 A
Explanation:
Lamp is rated at 300 mA
I_lamp = 0.3 A
Voltage is; V = 3V
Thus; Resistance is given by;
R = V/I
R = 3/0.3
R = 10 ohms
Now, since the ammeter of 5 ohms is connected in series with the lamp. Thus equivalent resistance;
R_eq = 10 + 5
R_eq = 15 ohms
Ammeter current will be;
I = V/R_eq
I = 3/15
I = 0.2 A
