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kifflom [539]
3 years ago
14

Given the Arithmetic sequence A1,A2,A3,A4 44, 51, 58, 65 What is the value of A39?

Mathematics
2 answers:
jenyasd209 [6]3 years ago
8 0
This is an arithmetic sequence because there is a common difference between terms, a constant found when subtracting the preceding term from any term in the sequence.  In this case the common difference is 7.

Any arithmetic sequence can be expressed as:

a(n)=a+d(n-1), a=initial value, d=common difference, n=term number

Here we have a=44 and d=7 so

a(n)=44+7(n-1)

a(n)=44+7n-7

a(n)=7n+37, so the 39th term is:

a(37)=7(37)+7

a(37)=266

I am assuming that 44 is the first term, not the 5th term...if 44 was the fifth term let me know and I will edit to reflect that...
snow_lady [41]3 years ago
6 0
This is an arithmetic sequence because there is a common difference between terms, a constant found when subtracting the preceding term from any term in the sequence.  In this case the common difference is 7.

Any arithmetic sequence can be expressed as:

a(n)=a+d(n-1), a=initial value, d=common difference, n=term number

Here we have a=44 and d=7 so

a(n)=44+7(n-1)

a(n)=44+7n-7

a(n)=7n+37, so the 39th term is:

a(37)=7(37)+7

a(37)=266

I am assuming that 44 is the first term, not the 5th term...if 44 was the fifth term let me know and I will edit to reflect that...
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