With the increase in the temperature of the star, the brightness of the stars will also increase.
<u>Explanation:</u>
The brightness and surface temperature of stars ordinarily increment with age. A star stays close to its underlying situation on the fundamental arrangement until a lot of hydrogen in the center has been devoured, at that point starts to advance into a progressively brilliant star.
The brightness of a star relies upon its structure and how far it is from the planet. Space experts characterize star brilliance as far as clear extent — how splendid the star shows up from Earth — and outright greatness — how brilliant the star shows up at a standard separation
Answer:
See the attached image and the explanation below
Explanation:
We must draw a schematic of the described problem, after the sketch it is necessary to make a free body diagram, at the time before and after cutting the cord.
These free body diagrams can be seen in the attached image.
First we perform a sum of forces on the x & y axes before cutting the cord, to be able to find the T tension of the wire. (This analysis can be seen in the attached image).
In this way we get the T-wire tension equation, before cutting.
Now we make another free body diagram, for the moment when the wire is cut (see in the attached diagram).
It is important to clarify that when the cord is cut, the system will no longer be in statically, therefore newton's second law will be used for summation of forces which will be equal to the product of mass by acceleration.
Finally with equations 1 and 2 we can find the K ratio.
Sometimes arithmetic problems can be solved much more easily using the dimensional analysis approach. You focus on the units of the given information. Then, you manipulate them applying the laws of algebra where like units cancel, in order to end up with the unit of the unknown.
Given:
-50 nc/step
31 steps
Unknown: charge
Thus,
Charge = -50 nc/step * 31 steps =<em> -1550 nc</em>
The average velocity of the object would be :
[s (1.5) - s (1)] / 0.5
= [8.75 -15] / 0.5
= 12.5 m/s
Hope this helps