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3 years ago

Which element has the greatest number of valence electrons?

Physics

1 answer:

nalin [4]3 years ago

3 0

Answer: Option B) oxygen (O)

Explanation:

The number of valence electrons in an element refers to the number of electrons in its outermost shell.

Hence, for each of the given elements, they are as follows:

- Phosphorus (P) has an atomic number of 15, with an electronic configuration of 1s2, 2s2 2p6, 3s2 3p3. Hence, it has 5 valence electrons.

- Oxygen (0) has an atomic number of 8, with an electronic configuration of 1s2, 2s2 2p6. Hence, it has 6 valence electrons.

- Sodium (Na), has an atomic number of 11, with an electronic configuration of 1s2, 2s2 2p6, 3s1. Hence, it has 1 valence electron.

- Magnesium (Mg) has an atomic number of 12, with an electronic configuration of 1s2, 2s2 2p6, 3s2. Hence, it has 2 valence electrons.

Thus, oxygen with 6 outermost electrons has the greatest number of valence electrons among the given elements.

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Your high-fidelity amplifier has one output for a speaker of resistance 8 Ω. How can you arrange two 8-Ω speakers, one 4-Ω speak

ANTONII [103]

Answer:

(a) 8Ω (b) Ratio = Parra/P8 ohm = 1

Explanation:

Solution

Recall that,

An high-fidelity amplifier has one output for a speaker of resistance of = 8 Ω

Now,

(a) How can two 8-Ω speakers be arranged, when one = 4-Ω speaker, and one =12-Ω speaker

The Upper arm is : 8 ohm, 8 ohm

The Lower arm is : 12 ohm, 4 ohm

The Requirement is = (16 x 16)/(16 + 16) = 8 ohm

(b) compare your arrangement power output of with the power output of a single 8-Ω speaker

The Ratio = Parra/P8 ohm = 1

8 0

3 years ago

Two spheres are cut from a certain uniform rock. One has radius 4.50 cm. The mass of the other is five times greater. Find its r

Sonja [21]

Vol of sphere = 4/3 pi r^2.density of sphere = mass/volume.mass = densityxvolumesphere 1. mass = density x 4/3 pi 4.5^2sphere 2 5mass = density x 4/3 pi r^25=4/3 pi r^2 divided by 4/3 pi 4.5^25=r^2 divided by 4.5^25x4.5^2=r^2root(5x4.5^2)=r4.5 root 5 = r

4 0

3 years ago

Read 2 more answers

A 29.0 kg beam is attached to a wall with a hi.nge while its far end is supported by a cable such that the beam is horizontal.

castortr0y [4]

The vertical component of force exerted by the hi.nge on the beam will be,142.10N.

To find the answer, we need to know more about the tension.

<h3>How to find the vertical component of the force exerted by the hi.nge on the beam?</h3>

Let's draw the free body diagram of the system.
To find the vertical component of the force exerted by the hi.nge on the beam, we have to balance the total vertical force to zero.

$F_V+T sin\alpha -mg=0\\F_V=mg-Tsin\alpha \\$

To find the answer, we have to find the tension,

$Tlsin\alpha - mg\frac{l}{2}sin\beta =0\\ \\Tlsin\alpha = mg\frac{l}{2}sin\beta\\\\Tsin57=\frac{mg}{2}sin90\\\\T=\frac{mg}{2sin57} =169.43N$

Thus, the vertical component of the force exerted by the hi.nge on the beam will be,

$F_V=(29*9.8)-(169.43*sin57)=142.10N$

Thus, we can conclude that, the vertical component of force exerted by the hi.nge on the beam will be,142.10N.

Learn more about the tension here:

brainly.com/question/28106868

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5 0

2 years ago

Read 2 more answers

(I) In a ballistic pendulum experiment, projectile 1 results in a maximum height h of the pendulum equal to 2.6 cm. A second pro

Kipish [7]

Answer:

The second projectile was 1.41 times faster than the first.

Explanation:

In the ballistic pendulum experiment, the speed (v) of the projectile is given by:

$v = \frac{m + M}{m} \cdot \sqrt{2gh}$

<em>where m: is the mass of the projectile, M: is the mass of the pendulum, g: is the gravitational constant and h: is the maximum height of the pendulum. </em>

To know how many times faster was the second projectile than the first, we need to take the ratio for the velocities for the projectiles 2 and 1:

$\frac{v_{2}}{v_{1}} = \frac{\frac{m_{2} + M}{m_{2}} \cdot \sqrt{2gh_{2}}}{\frac{m_{1} + M}{m_{1}} \cdot \sqrt{2gh_{1}}}$ (1)

<em>where m₁ and m₂ are the masses of the projectiles 1 and 2, respectively, and h₁ and h₂ are the maximum height reached by the pendulum by the projectiles 1 and 2, respectively. </em>

Since the projectile 1 has the same mass that the projectile 2, we can simplify equation (1):

$\frac{v_{2}}{v_{1}} = \frac{\sqrt{h_{2}}}{\sqrt{h_{1}}}$