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3 years ago

What is the sun? I'm really confused and we are studying the solar system please help?

2 answers:

5 0

The sun is a big ball of gas that has tornados of fire and lil ball of fire explosions its the hotest thing in our solar system and if u look up in the sky u see a bright ball of light which is called the sun and u cant miss it in the solar system cause everything evolves around it.

stellarik [79]3 years ago

4 0

The sun is a star (a giant ball of burning gases).

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At time t = 0, a 2150-kg rocket in outer space fires an engine that exerts an increasing force on it in the +x-direction. This f

Digiron [165]

Answer:

a) A = 500 N/s²

b) I = 5812.50 N-s

c) Δv = 2.7034 m/s

Explanation:

Given info

m = 2150 kg

F(t) = At²

F(1.25 s) = 781.25 N

a) A = ?

We use the equation

F(t) = At² ⇒ 781.25 N = A*(1.25 s)²

⇒ A = F(t) / t² = (781.25 N) / (1.25 s)²

⇒ A = 500 N/s²

b) I = ? if 2.00 s ≤ t ≤ 3.50 s

we apply the equation

I = ∫F(t) dt = ∫At² dt = A ∫t² dt = (500/3)*t³ + C

Since the limits of integration are 2 and 3.5, we obtain

I = (500/3)*((3.5)³-(2)³) = 5812.50 N-s

c) Δv = ?

we can apply the equation

I = m*Δv ⇒ Δv = I / m

⇒ Δv = 5812.50 N-s / 2150 kg

⇒ Δv = 2.7034 m/s

7 0

3 years ago

Why are satellites placed into orbit at least 150 km above Earth’s surface?

dybincka [34]

Because its just enough to where its not out f the gravitational pull and not close enough to be pulled back to earth. Hope it helps

8 0

3 years ago

Read 2 more answers

Infrared radiation has frequencies from 3.0×1011 to 3.0×1014 Hz, whereas the frequency region for radio wave radiation is 3.0×10

expeople1 [14]

Answer:

1. The speed of infrared radiation is greater than radio wave radiation

2. The wavelength of infrared radiation is less than the radio wave radiation

Explanation:

Given:

The radio wave radiation N₁ is 3x10⁵ to 3x10⁷ Hz and the infrared radiation N₂ is 3x10¹¹ to 3x10¹⁴ Hz. The speed is:

$\frac{velocity_{2} }{velocity_{1} } =\frac{3x10^{11} }{3x10^{5} } to\frac{3x10^{14} }{3x10^{7} } =1x10^{6} to1x10^{7}$

1. The speed of infrared radiation is greater than radio wave radiation

2. The wavelength is:

λ = C/N

where more C, less λ

Then, the wavelength of infrared radiation is less than the radio wave radiation

4 0

3 years ago

The body falls in a free fall 11s.Calculate: a) from what height the body of the paddle) what path did it fall during the last s

JulsSmile [24]

Answer:

a) h = 593.50 m

b) h₁₁ = 103 m

c) vf = 107.91 m/s

Explanation:

We will use second equation of motion to find the height:

$h = v_{i}t + (\frac{1}{2})gt^2$

where,

h = height = ?

vi = initial speed = 0 m/s

t = time taken = 11 s

g = 9.81 /s²

Therefore,

$h = (0\ m/s)(11\ s) + (\frac{1}{2})(9.8\ m/s^2)(11\ s)^2\\\\$

h = 593.50 m

For the distance travelled in last second, we first need to find velocity at 10th second by using first equation of motion:

$v_{f} = v_{i} + gt$

where,

vf = final velocity at tenth second = v₁₀ = ?

t = 10 s

vi = 0 m/s

Therefore,

$v_{10} = 0\ m/s + (9.81\ m/s^2)(10\ s)\\\\v_{10} = 98.1\ m/s$

Now, we use the 2nd equation of motion between 10 and 11 seconds to find the height covered during last second:

$h = v_{i}t + (\frac{1}{2})gt^2$

where,

h = height covered during last second = h₁₁ = ?

vi = v₁₀ = 98.1 m/s

t = 1 s

Therefore,

$h_{11} = (98.1\ m/s)(1\ s) + (\frac{1}{2})(9.8\ m/s^2)(1\ s)^2\\\\$

h₁₁ = 103 m

Now, we use first equation of motion for complete motion:

$v_{f} = v_{i} + gt$

where,

vf = final velocity at tenth second = ?

t = 11 s

vi = 0 m/s

Therefore,

$v_{f} = 0\ m/s + (9.81\ m/s^2)(11\ s)$

vf = 107.91 m/s

8 0

4 years ago

Is oxygen a reactant or product

dezoksy [38]

Answer:

Methane and oxygen (oxygen is a diatomic — two-atom — element) are the reactants, while carbon dioxide and water are the products

Explanation:

3 0

3 years ago

Read 2 more answers