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Andre45 [30]
3 years ago
11

Solve and round to the correct number of significant figures: 129 ÷ 29.20

Chemistry
1 answer:
Scilla [17]3 years ago
5 0

4.42

Because when you divide 129/29.20, you get a long string of numbers. 4.417808219178082...

So you round to the significant figure which in this case is 2 decimal places because 29.20 has 2 decimal places.

PS did you draw that car? Cuz im into drawing cars too.

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Four oranges were placed in a series circuit. Approximately what voltage did this produce?
vampirchik [111]

Answer:

Four times the original amount if only one orange was used

Explanation:

We can assume that the oranges all have equal voltages. Connecting them in series will have an increasing effect on the voltage delivered. In our case, this will produce 4 times the voltage of the circuit when only one orange is used.

Whenever simple cells are connected in series, the voltages of the individual cells are added up to form the voltage of the whole circuit.

Let us assume that the voltage of each of the oranges is approximately 0.9 volts. The Voltage produced when the 4 oranges are joined in series is 0.9 + 0.9 + 0.9 + 0.9 = 3.6 volts

3 0
3 years ago
The atomic number of lead (Pb) is 82. Its mass number is 207. How many protons, neutrons, and electrons does this neutral atom o
AveGali [126]
An element’s atomic number is equal to the number of protons in that element’s nucleus. The mass number is the total number of an atom’s protons and neutrons. Protons have a positive charge; electrons have a negative charge; and neutrons are electrically neutral.

Putting it all together, given that the atomic number of lead is 82, the number of protons a lead atom contains is 82. The number of neutrons would be the difference between 207 and 82, or 125 neutrons. Finally, since you have a neutral atom, there must be an equal number of electrons as the number of protons—that is, 82 electrons.

Thus, you’ve got 82 protons, 125 neutrons, and 82 electrons.
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3 years ago
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BAS might be an improperly capitalized: BAs, BaS

PTF2 might be an improperly capitalized: PtF2

BAF2 might be an improperly capitalized: BaF2

PTS might be an improperly capitalized: PtS

8 0
3 years ago
Read 2 more answers
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3 years ago
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