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zloy xaker [14]
3 years ago
13

Please help me I will give you the brain thing with extra points if you help me, please. I need to get this right. 3/10

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
5 0

Answer:

I'd say its speed but not to sure

Explanation:

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I build a fire and burn 3 logs. Apply the Law of Conservation of Matter
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What are deltaTb and deltaTf for an aqueous solution that is 1.5g nacl in 0.250kg h2o? Given Kb=0.51 C/m and kr=1.86 C/m
bulgar [2K]

Answer:

T_f for given question is 2.79 and T_b is 0.52

\Delta T_b = I \times K_b \times m {i- vant hoff’s constant ; Kb- constant ; m molarity }

M = no. of moles of the solute present in one kg of solution

Let the weight of amount of solute be “w” and its molecular mass be “M”

Let the mass of the solvent in the given question be “x”

\Delta T_b = I \times K_b \times (w/M)/ x

\Delta T_b = I \times K_b \times w/Mx

\Delta T_b = 1 \times 0.51 \times1.5/(0.250 \times 58.44) = 0.052

\Delta T_f = M \times K_f = 1.86 \times 1.5 = 2.79

4 0
3 years ago
I have asked this already!!!!!
stellarik [79]

Answer:

01) Cu tting hair is a physical change. reason-1

02) Cooking can be either one, but I would choose chemical reason-3

03) Ice cream melting is a physical change reason-2

Explanation:

6 0
2 years ago
If 4000 g of Fe2O3 reacts, how many moles of CO are needed?<br> (add work)
7nadin3 [17]

Answer:

75.15 mol.

Explanation:

  • Firstly, we need to write the balanced equation of the reaction:

<em>Fe₂O₃ + 3CO → 2Fe + 3CO₂.</em>

It is clear that 1.0 mole of Fe₂O₃ reacts with 3.0 moles of CO to produce 2.0 moles of Fe and 3.0 moles of CO₂.

∴ Fe₂O₃ reacts with CO with (1: 3) molar ratio.

  • we need to calculate the no. of moles of (4000 g) of Fe₂O₃:

<em>no. of moles of Fe₂O₃ = mass/molar mass</em> = (4000 g)/(159.69 g/mol) = <em>25.05 mol.</em>

<u>Using cross multiplication:</u>

1.0 mole of Fe₂O₃ needs → 3.0 moles of CO,

∴ 25.05 mole of Fe₂O₃ needs → ??? moles of CO.

<em>∴ The no. of moles of CO needed</em> = (3.0 mol)(25.05 mol)/(1.0 mol) =<em> 75.15 mol.</em>

5 0
3 years ago
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