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makkiz [27]
3 years ago
10

Which concern is the LEAST important when using a compound light microscope to view a sample of paramecia? A) obtaining good res

olution B) obtaining sufficient contrast C) recognizing the subject when one sees it D) having sufficient magnification available..........................THE ANSWER IS D....stg
Chemistry
2 answers:
Iteru [2.4K]3 years ago
8 0

Answer:

D)

Explanation:

The compound light microscope is a microscope that has more than one lens and its light source. Because of the various lens presented, having a sufficient magnification is not a concern.

However, only magnification doesn't indicate that it will be possible to view a sample, it's necessary some contrast to separate all the species presented, a good resolution (so the sample will be the focus), and also recognizing the subject when one sees it.

shepuryov [24]3 years ago
4 0
D is your answer to your quistion :) 
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Answer:

1. Gold is valuable because of its high quality physical and chemical properties

2. The gold mines where the state's property in both Egyptian and Roman civilizations

3. The elixir of life is akin to the philosopher stone. It is a chemical portion that when drank, grants eternal life

4. The contribution of alchemists to modern chemistry, includes the formulation of the first ideological periodic table, the distillation process, metalworking, gunpowder, glass, ink, paints, cosmetics and many other innovations

Explanation:

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2 years ago
Does SiO2 also equal Si2O4?<br> (silicon atom 1 oxygen atom 2 = silicon atom 2 oxygen atom 4?)
Norma-Jean [14]

Answer:

7

Explanation:

that is the anwer of the question

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2 years ago
The hormone adrenaline can affect only cells with
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Answer:

appropriately shaped receptors

Explanation:

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3 years ago
Un mol de Neón ocupa un volumen de 5 lt y una temperatura 300°K, cuál será su volumen si la temperatura disminuye en 50 °K, P y
Anna [14]

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2 years ago
A sample of oxygen gas in one container has a volume of 20.0mililiter at 297 K and 101.3 kPa. The entire sample is transferred t
VashaNatasha [74]

Answer: V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{P_1V_1T_2}{T_1P_2}

where,

P_1 = initial pressure of gas = 101.3 kPa

P_2 = final pressure of gas = 94.6 kPa

V_1 = initial volume of gas = 20.0 ml

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 297K

T_2 = final temperature of gas = 283K

Now put all the given values in the above equation, we get the final volume of gas.

V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

V_2=20.4ml

Thus the correct numerical setup for calculating the new volume is \frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

3 0
3 years ago
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