Answer:
A will be much less than 0 degrees
Explanation:
See the graph
https://prnt.sc/10ahuzc
Answer:
- The answer is the concentration of an NaOH = 1.6 M
Explanation:
The most common way to solve this kind of problem is to use the formula
In your problem,
For NaOH
C₁ =?? v₁= 78.0 mL = 0.078 L
For H₂SO₄
C₁ =1.25 M v₁= 50.0 mL = 0.05 L
but you must note that for the reaction of NaOH with H₂SO₄
2 mol of NaOH raect with 1 mol H₂SO₄
So, by applying in above formula
- (C₁ * 0.078 L) = (2* 1.25 M * 0.05 L)
- C₁ = (2* 1.25 M * 0.05 L) / (0.078 L) = 1.6 M
<u>So, the answer is the concentration of an NaOH = 1.6 M</u>
Answer:
A. Rock fragments are layered and pressurized over time.
Explanation:
Sedimentary rocks are derived from pre-existing rocks that have been subjected to agents of denudation, weathered, transported and deposited within a basin.
In the basin, the sediments are accumulated in their final resting position.
- Sediments are accumulated as layers on top of one another.
- The pressure of the sediment on top of another forces out water and presses the layers into sheets.
- Over time, the compression leads to lithification of the rock.
- During lithification, compaction and cementation occurs.
<span>((P1V1/T1)=(P2V2/T2))</span>
This is a combination reaction. Look at the 2 elements on left and a compound on the right.
