What percentage of the filtrate's water that enters bowman's capsule is reabsorbed into the blood? select one:

1 answer:

3 0

99% of the filtrate's water that enter bowman's capsule is reabsorbed into the blood. This is because the water and the salts contained in the filtrate are needed for optimal functioning of the body system.

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Which gas is used to take out blueprint

tiny-mole [99]

The blueprint process

The best known is a process using ammonium ferric citrate and potassium . The paper is impregnated with a solution of ammonium ferric citr

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2. Calculate the number-average molecular weight of a random poly (isobutylene-isoprene) copolymer in which the fraction of isob

Phoenix [80]

Answer : The number-average molecular weight is, 97500 g/mol

Explanation :

First we have to calculate the molecular weight of isobutylene and isoprene.

The molecular formula of isobutylene and isoprene is, $C_4H_8$ and $C_5H_8$

Molecular weight of $C_4H_8$ = 4(12 g//mol) + 8(1 g/mol) = 56 g/mol

Molecular weight of $C_5H_8$ = 5(12 g//mol) + 8(1 g/mol) = 68 g/mol

Now we have to calculate the average repeat molecular weight.

Average repeat molecular weight = $0.25\times (56g/mol)+(1-0.25)\times (68g/mol)$

Average repeat molecular weight = 65 g/mol

Now we have to calculate the number-average molecular weight.

Number-average molecular weight = Average repeat molecular weight × Degree of polymerization

Number-average molecular weight = (65 g/mol) × (1500)

Number-average molecular weight = 97500 g/mol

Thus, the number-average molecular weight is, 97500 g/mol

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3 years ago

ANSWER d is the corresect answer

loris [4]

Answer:

d is the correct answer

Explanation:

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30.0 mL of 0.50 M NaOH to neutralize 15.0 mL of HNO3, what is the concentration (molarity) of the HNO3?

vredina [299]

First find the no. of moles of NaOH :
30/1000 = 0.3 dm3 so no. of moles = 0.3*0.5 = 0.15 moles 

as NaOH reacts with HNO3 in a ratio of one to one, there must have been 0.15 moles of HNO3 too 
moles/volume = concentration 
volume= 15/1000 = 0.15 dm3 

concentration = 1.15/0.15 = 1 mol.dm-3 

The quicker way would be to realize that you used twice as much NaOH so the HNO3 had to be twice as strong

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A chemical Property I hope this helps friend ^^

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