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Umnica [9.8K]
3 years ago
9

PLSSSS HELP this is science

Chemistry
2 answers:
jenyasd209 [6]3 years ago
4 0

Answer:

<h2>The answer is C </h2>

Explanation:

when a car begins to slow down the speed that it was going will decrease. Which means that it is an example of deceleration.

djyliett [7]3 years ago
4 0

Answer:

The answers would be : ( a car approaching a red light )

15 N .

F= m.a ----> 15 = 5.3

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A balloon filled with 0.500 L of air at sea level is submerged in the water to a depth that produces a pressure of 3.25 atm. Wha
mario62 [17]

Answer:

Option a . 0.154L

Explanation:

P₁ . V₁ = P₂ . V₂

when we have constant temperature and constant moles for a certain gas.

At sea level, pressure is 1 atm so:

0.5 L . 1atm = V₂ . 3.25 atm

(0.5L . 1atm) / 3.25 atm = 0.154 L

6 0
3 years ago
Consider an endothermic reaction C(s) CO2(g)2CO(g) If such a system at equilibrium is heated and compressed at the same time, wh
RSB [31]

Answer:

A. It will shift to the left

Explanation:

In the equilibrium:

C(s) ⇄ CO2(g)2CO(g)

The system will shift to the right if any change stimulate the production of gas -LeChatelier's principle-; in the same way, if a change doesn't favors the production of gas the system will shift to the left producing less gas.

The changes that increasing the pressure of the system, doesn't favors the gas production doing the system shift to the left.

A gas that is heated expands itsellf doing the pressure increases.

In the same way, if you compress the gas, the gas increases its pressure.

Thus, both changes increase pressure of the gas doing the system shift to the left.

<h3>A. It will shift to the left </h3>

6 0
4 years ago
Four ice cubes at exactly 0 ∘c with a total mass of 52.5 g are combined with 160 g of water at 90 ∘c in an insulated container.
horrorfan [7]
Heat gained by ice cubes would be equal to the - heat lost by warm water 

The moles of ice is: 50.5 g / 18.0 g/mol = 2.81 mol 

Heat required to melt all of the ice is equal to: 2.81 mol X 6.02 kJ/mol = 16.9 kJ = 16890 J 

Now, know whether the warm water will still be above 0C when it loses this much heat:
-1690 J = 160 g (4.184 J/gC) (Delta T) Delta T = -25C 

In order to solve for the final temperature, going back to include warming of the melted ice to a final temperature: 

q(ice/water) = - q(warm water) 

moles (Delta Hf) + m c (T2-T1) = - m c (T2-T1) 

50.5 g / 18.0 g/mol = 2.81 mol 

2.81 mol X 6.02 kJ/mol + 50.5g (4.184 J/gC) (T2-0) = -160g (4.184 J/gC) ( T2-80) 

16916 + 211.3T2 = -669.4 T2 + 53555 

36639 = 880.7 T2 

T2 = 41.6 C
6 0
3 years ago
Read 2 more answers
10. Which is a practical application of freezing-point depression?
IceJOKER [234]

Answer:

1.

Explanation:

its the practical example

5 0
3 years ago
Help me please<br> ( I'll give brainlist to whoever answers right)
devlian [24]
A goes with u, C with G, and T with A
4 0
3 years ago
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