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Sindrei [870]
3 years ago
16

Wilam made a chart to summarize the results of experiments with the photoelectric effect. Which best describes how to correct Wi

lam’s error? The first result should state that frequencies of light that were lower than the frequency threshold of the metal could not eject electrons. The second result should state that as soon as light struck the metal, protons were ejected. The second result should state that just before light struck the metal, electrons were ejected. The third result should state that the kinetic energy of the ejected electrons depends only on the frequency of the photons.
Physics
2 answers:
Arlecino [84]3 years ago
7 0
A is the answer. I jjust took the quiz.
rodikova [14]3 years ago
3 0
The first result should state that frequencies of light that were lower than the frequency threshold of the metal could not eject electrons<span>
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When an object like a tree is illuminated by the sun, and you are looking toward the tree, light rays leave the object _________
Dima020 [189]

Objects absorb and reflect light differently depending on their physical characteristics, such as their shape or composition. Thanks to the reflection we can see the objects. Reflection can be defined as the change of direction of a wave, which, when in contact with the separation surface between two changing means, returns to the point where it originated. When the light illuminates the object, such as the tree, the rays of light will disperse in all directions allowing observation.

The correct answer is A. From every point on the surface of the tree, and in every direction

6 0
3 years ago
65 POINTS! PLEASE ANSWER EVERY QUESTION! NEED HELP ASAP!
otez555 [7]
Maybe you can split up the questions. I will try to answer your first question.

1. In an elastic collision, momentum is conserved. The momentum before the collision is equal to the momentum after the collision. This is a consequence of Newton's 3rd law. (Action = Reaction)

2. Momentum: p = m₁v₁ + m₂v₂

m₁ mass of ball A
v₁ velocity of ball A
m₂ mass of ball B
v₂ velocity of ball B

Momentum before the collision:
p = 2*9 + 3*(-6) = 18 - 18 = 0

Momentum after the collision:
p = 2*(-9) + 3*6 = -18 + 18 = 0

3: mv + m(-v) = m(-v) + m(v)
the velocities would reverse.

4.This question is not factual since the energy of an elastic collision must also be conserved. The final velocities should be: v₁ = -1 m/s and v₂ = 5 m/s. That said assuming the given velocities were correct:
before collision
p = 10*3 + 5*(-3) = 30 - 15 = 15
after collision:
p = 10*(-2) + 5 * v₂ = 15
v₂ = 7

5.You figure out.



3 0
3 years ago
What do you know about nuclear energy?​
aev [14]

Answer:

Nuclear energy comes from splitting atoms in a reactor to heat water into steam, turn a turbine and generate electricity. Ninety-three nuclear reactors in 28 states generate nearly 20 percent of the nation's electricity, all without carbon emissions because reactors use uranium, not fossil fuels.

<h2>please follow me</h2>
6 0
2 years ago
If you sleep 33% in a day, how many hours is that?
lesantik [10]

In this question, one has to carefully understand that the total number of hours in the day can never be more that 24 hours. based on this important fact the answer to the question can be very easily deduced. The only requirement is calculating perfectly.
Number of hours in a day = 24 hours
Percentage of hours of sleep in a day = 33%
Amount of sleep in the day = (33/100) * 24
                                             = 7.92 hours
So 33% of sleep in a day is equal to 7.92 hours. I hope this answer has helped you. In future you can keep the procedure in mind for solving such problems.
5 0
3 years ago
The moment of inertia of a uniform-density disk rotating about an axle through its center can be shown to be . This result is ob
Naddik [55]

(a) 0.2888 kg m^2

The moment of inertia of a uniform-density disk is given by

I=\frac{1}{2}MR^2

where

M is the mass of the disk

R is its radius

In this problem,

M = 16 kg is the mass of the disk

R = 0.19 m is the radius

Substituting into the equation, we find

I=\frac{1}{2}(16 kg)(0.19 m)^2=0.2888 kg m^2

(b) 142.5 J

The rotational kinetic energy of the disk is given by

K=\frac{1}{2}I\omega^2

where

I is the moment of inertia

\omega is the angular velocity

We know that the disk makes one complete rotation in T=0.2 s (so, this is the period). Therefore, its angular velocity is

\omega=\frac{2\pi}{T}=\frac{2\pi}{0.2 s}=31.4 rad/s

And so, the rotational kinetic energy is

K=\frac{1}{2}(0.2888 kg m^2)(31.4 rad/s)^2=142.5 J

(c) 9.07 kg m^2 /s

The rotational angular momentum of the disk is given by

L=I\omega

where

I is the moment of inertia

\omega is the angular velocity

Substituting the values found in the previous parts of the problem, we find

L=(0.2888 kg m^2)(31.4 rad/s)=9.07 kg m^2 /s

8 0
3 years ago
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