a.
The work done by a constant force along a rectilinear motion when the force and the displacement vector are not colinear is given by:
where F is the magnitude of the force, theta is the angle between them and d is the distance.
The problen gives the following data:
The magnitude of the force 750 N.
The angle between the force and the displacement which is 25°
The distance, 26 m.
Plugging this in the formula we have:
Therefore the work done is 17673 J.
b)
The power is given by:
the problem states that the time it takes is 6 s. Then:
Therefore the power is 2945.5 W
you can check attachment for answer.
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Answer:
The temperature of the metal is 
Explanation:
From the question we are told that
The mass of the metal is 
The specific heat of the metal is 
The mass of the oil is 
The temperature of the oil is 
The specific heat of oil is 
The equilibrium temperature is 
According to the law of energy conservation
Heat lost by metal = heat gained by the oil
So
The quantity of heat lost by the metal is mathematically represented as
=> 
Where 
the temperature of metal before immersion
The negative sign show heat lost
The quantity of gained t by the metal is mathematically represented as
=> 
So
substituting values
=>
Answer:
A - Crest, B - amplitude, C - wavelength, D - trough
Explanation:
Answer:
The speed after being pulled is 2.4123m/s
Explanation:
The work realize by the tension and the friction is equal to the change in the kinetic energy, so:
(1)
Where:
Because the work made by any force is equal to the multiplication of the force, the displacement and the cosine of the angle between them.
Additionally, the kinetic energy is equal to 
, so if the initial velocity 
is equal to zero, the initial kinetic energy 
is equal to zero.
Then, replacing the values on the equation and solving for 
, we get:
So, the speed after being pulled 3.2m is 2.4123 m/s
