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4 years ago

What is the difference between a total solar eclipse, an annular solar eclipse, and a partial solar eclipse.

2 answers:

5 0

hii! In a total eclipse, the disk of the Sun is fully obscured by the Moon. In partial and annular eclipses, only part of the Sun is obscured. ... Total solar eclipses are rare at any particular location because totality exists only along a narrow path on the Earth's surface traced by the Moon's full shadow or umbra.

lozanna [386]4 years ago

4 0

The total solar eclipse is the eclipse in which the Sun gets completely covered by the Moon and Solar Corona can be seen whereas in case of partial solar eclipse, the Sun is partially covered by the Moon and Solar Corona can’t be seen whereas, in case of annular solar eclipse, the moon is further away from the Earth than in case of Total solar eclipse.

Corona is visible in case of the Total solar eclipse.

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(50 POINTS) HELP!!!!!! WILL GIVE BRAINLIEST

zepelin [54]

C) During chemical reaction, total mass remains the same.

This is because due to the law of conservation of mass, stating that in a chemical reaction, neither mass will be created nor destroyed. So, the total mass will not change when chemical reactions occur.

7 0

3 years ago

Moving from the element with atomic number 10 to atomic number 11 on the periodic table, there is a change in reactivity. In thr

bazaltina [42]

Answer:

Explanation:

Ne has its outside shell full of electrons; therefore, its reaction with other elements is minimal if at all. Na, the next element, has 1 more proton and 1 more electron. More importantly that added electron is in the outside shell. It can fill that shell by ADDing 7 more electrons or LOSing the one electron. Obviously, it loses the one electron and it does so with gusto which makes Na a very reaction element while Ne is not reactive at all. Now follow oobleck's instructions, add what you read to what I've written,then summarize all of it in your own words.

7 0

3 years ago

2. Which of the following wavelength properties would require a stopwatch to measure?

katovenus [111]

Answer:

A. wavelength

Explanation:

The others are about sound and how high it is. That has nothing to do with time.

3 0

3 years ago

Read 2 more answers

An object is formed by attaching a uniform, thin rod with a mass of mr = 6.85 kg and length L = 5.76 m to a uniform sphere with

Ket [755]

Answer:

Part a)

$I = 1879.7 kg m^2$

Part b)

$\alpha = 0.70 rad/s^2$

Part c)

$I = 153.8 kg m^2$

Part 4)

angular acceleration will be ZERO

Part 5)

$I = 345.6 kg m^2$

Explanation:

Part a)

Moment of inertia of the system about left end of the rod is given as

$I = \frac{m_r L^2}{3} + (\frac{2}{5} m_s R^2 + m_s(R + L)^2)$

So we have

$I = \frac{m_r(4R)^2}{3} + (\frac{2}{5}(5m_r) R^2 + (5m_r)(R + 4R)^2)$

$I = \frac{16}{3}m_r R^2 + (2m_r R^2 + 125 m_rR^2)$

$I = (\frac{16}{3} + 127)m_r R^2$

$I = (\frac{16}{3} + 127)(6.85)(1.44)^2$

$I = 1879.7 kg m^2$

Part b)

If force is applied to the mid point of the rod

so the torque on the rod is given as

$\tau = F\frac{L}{2}$

$\tau = 460(2R)$

$\tau = 460 \times 2 \times 1.44$

$\tau = 1324.8 Nm$

now angular acceleration is given as

$\alpha = \frac{\tau}{I}$

$\alpha = \frac{1324.8}{1879.7}$

$\alpha = 0.70 rad/s^2$

Part c)

position of center of mass of rod and sphere is given from the center of the sphere as

$x = \frac{m_r}{m_r + m_s}(\frac{L}{2} + R)$

$x = \frac{m_r}{6 m_r}(3R) = \frac{R}{2}$

so moment of inertia about this position is given as

$I = \frac{m_r L^2}{12} + m_r(\frac{L}{2} + \frac{R}{2})^2 + (\frac{2}{5} m_s R^2 + m_s(\frac{R}{2})^2)$

so we have

$I = \frac{m_r (16R^2)}{12} + m_r(\frac{5R}{2})^2 + \frac{2}{5}(5m_r)R^2 + (5m_r)(\frac{R^2}{4})$

$I = m_r R^2(\frac{16}{12} + \frac{25}{4} + 2 + \frac{5}{4})$

$I = 6.85(1.44)^2\times 10.83$

$I = 153.8 kg m^2$

Part 4)

If force is applied parallel to the length of rod

then we have

$\tau = \vec r \times \vec F$

$\tau = 0$

so angular acceleration will be ZERO

Part 5)

moment of inertia about right edge of the sphere is given as

$I = \frac{m_r L^2}{12} + m_r(\frac{L}{2} + 2R)^2 + (\frac{2}{5} m_s R^2 + m_s(R)^2)$

so we have

$I = \frac{m_r (16R^2)}{12} + m_r(4R)^2 + \frac{2}{5}(5m_r)R^2 + (5m_r)(R^2)$

$I = m_r R^2(\frac{16}{12} + 16 + 2 + 5)$

$I = 6.85(1.44)^2\times 24.33$

$I = 345.6 kg m^2$

6 0

3 years ago

Which of the following accurately describes junction diodes?

tatiyna

Correct answer choice is :

D) In a forward-biased setup, large numbers of charge carriers will be pulled across the junction and result in a large current.

Explanation:

P-n junction diode is the easiest mode of all the semiconductor tools. Despite, diodes act a significant role in many electronic appliances. A p-n junction diode can be utilized to change the alternating current to the direct current. These diodes are applied in power supply accessories. Battery attached across the p-n junction causes the diode forward biased, pushing particles from the n-type to the p-type and starting holes in a different way. Electrons and holes cross the junction and join. Photons are carried off as the electrons and holes recombine.

8 0

3 years ago

Read 2 more answers