Answer:
(a) ![K_{small}=4839.3J](https://tex.z-dn.net/?f=K_%7Bsmall%7D%3D4839.3J)
(b) ![K_{larger}=17406.4J](https://tex.z-dn.net/?f=K_%7Blarger%7D%3D17406.4J)
Explanation:
Given data
The angular velocity of two cylinders ω=257 rad/s
The mass of the two cylinders m=2.88 kg
The radius of small cylinder r₁=0.319 m
The radius of larger cylinder r₂=0.605 m
For Part (a)
The rotational kinetic energy of the cylinder is given by:
![K=\frac{1}{2}Iw^2](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7DIw%5E2)
Where I is rotational of inertia of solid cylinder about its central axis.
So
![K=\frac{1}{2}Iw^2\\ K=\frac{1}{2}(1/2mr^2)w^2](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7DIw%5E2%5C%5C%20K%3D%5Cfrac%7B1%7D%7B2%7D%281%2F2mr%5E2%29w%5E2)
Substitute the given values
So
![K_{small}=\frac{1}{4}(2.88kg)(0.319)^2(257rad/s)^2 \\K_{small}=4839.3J](https://tex.z-dn.net/?f=K_%7Bsmall%7D%3D%5Cfrac%7B1%7D%7B4%7D%282.88kg%29%280.319%29%5E2%28257rad%2Fs%29%5E2%20%5C%5CK_%7Bsmall%7D%3D4839.3J)
For Part (b)
![K=\frac{1}{2}Iw^2\\ K=\frac{1}{2}(1/2mr_{2}^2)w^2](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7DIw%5E2%5C%5C%20K%3D%5Cfrac%7B1%7D%7B2%7D%281%2F2mr_%7B2%7D%5E2%29w%5E2)
Substitute the given values
![K_{larger}=\frac{1}{4}mr_{2}^2w^2\\ K_{larger}=\frac{1}{4}(2.88kg)(0.605m)^2(257rad/s)^2\\ K_{larger}=17406.4J](https://tex.z-dn.net/?f=K_%7Blarger%7D%3D%5Cfrac%7B1%7D%7B4%7Dmr_%7B2%7D%5E2w%5E2%5C%5C%20K_%7Blarger%7D%3D%5Cfrac%7B1%7D%7B4%7D%282.88kg%29%280.605m%29%5E2%28257rad%2Fs%29%5E2%5C%5C%20K_%7Blarger%7D%3D17406.4J)
Answer:
Spirit of St. Louis
Explanation:
Charles Lindbergh was known as a prolific aviator during the early twentieth century. He is well known for the flight he took from Long Island, New York, to Paris, France. It was a continuous flight across the Atlantic Ocean.
The plane he used was the Spirit of St. Louis which took more than 33 hours to complete the journey. It was the first successful flight of this kind. The airplane flew from Long Island on May 20 and landed in Paris on May 21.
Answer:
Explanation:
the net force on the right left is 25 N and is directed upward
the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero
i hope this will help you
Answer:
Time, t = 13.34 seconds.
Explanation:
Given the following data;
Initial velocity, u = 85km/hr to meters per seconds = 85*1000/3600 = 23.61 m/s
Final velocity, v = 45km/hr to meters per seconds = 45*1000/3600 = 12.5 m/s
Acceleration, a = -3 km/hr/sec to meters per seconds square = -3*1000/3600 = -0.833m/s²
To find the time;
Acceleration = (v - u)/t
-0.833 = (12.5 - 23.61)/t
-0.833t = -11.11
t = 11.11/0.833
Time, t = 13.34 seconds.