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Jobisdone [24]
4 years ago
10

Which of the following are examples of projectile motion?

Physics
2 answers:
denis-greek [22]4 years ago
8 0

Answer:

A or C    I would pick C

Explanation:

astraxan [27]4 years ago
6 0

Answer: A and C

Explanation:

Just answered it on the apex quiz

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A bicyclist of mass 112 kg rides in a circle at a speed of 8.9 m/s. If the radius of the circle is 15.5 m, what is the centripet
kogti [31]
The centripetal force, Fc, is calculated through the equation, 
                                    Fc = mv²/r
where m is the mass,v is the velocity, and r is the radius. 
Substituting the known values,
                                     Fc = (112 kg)(8.9 m/s)² / (15.5 m)
                                         = 572.36 N
Therefore, the centripetal force of the bicyclist is approximately 572.36 N. 
4 0
3 years ago
Read 2 more answers
Why are SI units used for scientific works ?​
sineoko [7]
Energy can be one answer! There are many, but energy is a main one.
5 0
3 years ago
Read 2 more answers
Please help!!
sukhopar [10]

Answer:

<u>: WHY DIDN'T THE POD DOCK LIKE IT WAS SUPPOSED TO DO?</u><u> </u>

<u>ANSWER</u><u>;</u>

The force exerted by the thrusters caused the pod to change direction.

WHAT NEW THEORIES DO YOU HAVE?

ANSWER;

This pod moved differently because it was more massive.

<em><u>C</u></em><em><u>A</u></em><em><u>R</u></em><em><u>R</u></em><em><u>Y</u></em><em><u>O</u></em><em><u>N</u></em><em><u>L</u></em><em><u>E</u></em><em><u>A</u></em><em><u>R</u></em><em><u>N</u></em><em><u>I</u></em><em><u>N</u></em><em><u>G</u></em><em><u>:</u></em><em><u>)</u></em>

3 0
2 years ago
A large sheet of charge has a uniform charge density of 9  μCm2. What is the electric field due to this charge at a point just
Alex73 [517]

Answer:

Explanation:

Surface charge density, σ = 9 μC/m² = 9 x 10^-6 C/m²

According to the Gauss theorem,

Electric field due to the sheet is given by

E = \frac {\sigma }{2\epsilon _{0}}

E = \frac{9\times 10^{-6}}{2\times 8.854\times 10^{-12}}

E = 5.08 x 10^5 N/C

7 0
3 years ago
A jogger hears a car alarm and decides to investigate. While running toward the car, she hears an alarm frequency of 872.10 Hz.
Nata [24]

Answer:

v = 4.18 m/s

Explanation:

given,

frequency of the alarm = 872.10 Hz

after passing car frequency she hear = 851.10 Hz

Speed of sound = 343 m/s

speed of the jogger = ?

speed of the

v_f = \dfrac{872.10-851.10}{2}

v_f =10.5\ Hz

v_o = 872.1 - 10.5

V_0 = 861.6\ Hz

The speed of jogger

v = \dfrac{v_1 \times 343}{v_0}-343

v = \dfrac{872.1 \times 343}{861.6}-343

v = 4.18 m/s

5 0
3 years ago
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