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r-ruslan [8.4K]
3 years ago
7

PLEASE HELP!!

Mathematics
1 answer:
storchak [24]3 years ago
7 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions. 
Among the choices provided above the function the Oscar graph is <span>
y=(−0.4)x+3y=(−0.4)x+3
</span>
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May someone please help me, please? This is about exponents by the way. About 5 questions I need help with.
Leno4ka [110]

Answer:

1. 1  

2. 1

3. 16/81

4. 3

5. 3

Step-by-step explanation:

5 0
2 years ago
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Work out the size of angle x.<br>X<br>140°<br>105°​
yKpoI14uk [10]

Answer:

- 65

Step-by-step explanation:

x + 140 + 105 = 180

x + 245 = 180

x = 180- 245 = - 65

3 0
3 years ago
Determine the center and radius of the following circle equation:<br> x2 + y2 – 10x + 8y + 40 = 0
antiseptic1488 [7]

Answer:

The center of this circle is (5, -4) and the radius is 1.

Step-by-step explanation:

First regroup these terms according to x and y :

x^2 - 10x + y^2 + 8y = -40

Next, complete the square for x^2 - 10x:  x^2 - 10x + 5^2 - 5^2.

and the same for y^2 + 8y:  y^2 + 8y + 16 - 16

Substituting these results into x^2 - 10x + y^2 + 8y = -40, we get:

x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40.

Next, rewrite x^2 - 10x + 25 and y^2 + 8y + 16 as squares of binomials:

Then x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40 becomes:

(x - 5)^2 + (y + 4)^2 - 25 - 16 = -40, or:

(x - 5)^2 + (y + 4)^2 = 1

This equation has the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius.  Matching like terms, we get h = 5, k = -4 and r = 1.

The center of this circle is (5, -4) and the radius is 1.

6 0
3 years ago
Read 2 more answers
I need help asap 3x + 1 over 4y2
Blababa [14]
Ok so first, write down the equation. We know that x=3 and y=4. You just basically plug in the terms into the variables. So it would be 3(3)+1/4(4)^2. Simplify that equation and you should get your answer :)
7 0
3 years ago
7-11<br> Show work <br> Explain work
GREYUIT [131]
27 = forty five to the secmventh
4 0
3 years ago
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