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2 years ago

For what values of x is the expression below defined?

Mathematics

1 answer:

AleksandrR [38]2 years ago

4 0

The answer is x>0 on apex for x value

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The product of a number and nine increase by four is 58 find the number

Art [367]

The number of the product is 9

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2 years ago

Which sequence of transformations will produce similar but not congruent figures?

RoseWind [281]

A dilation would produce a similar figure. Therefore, the sequence of transformations that will produce a similar but not congruent figures would be the first and the third option. Figure TUVWX is dilated by a scale factor of 6 and then rotated 90° counterclockwise around the origin; and figure TUVWX is reflected across the x-axis and dilated by a scale factor of 7. Hope this answers your question.

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3 years ago

What is the opposite of 12? NEED HELP FAST

Liono4ka [1.6K]

Answer:

-12

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the value of x?

SSSSS [86.1K]

All angles in a triangle add up to 180

180 = 9 + 15 + 2x - 1 + 3x

180 = 24 - 1 + 2x + 3x

180 = 23 + 5x

180 - 23 = 5x

157 = 5x

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3 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago