1/3 = 4/12
5/12 = 5/12
1/6 = 2/12
4/12 + 5/12 + 2/12 = 11/12
12/12 - 11/12 = 1/12
1/2 of milk is left over.
X^2 + 16x + 61 = 0
x^2 + 16x = -61
x^2 + 16x + 64 = -61 + 64
(x + 8)^2 = 3
x + 8 = (+-) sqrt 3
x = -8 (+-) sqrt 3
x = -8 + sqrt 3...and x = -8 - sqrt 3 <== ur solutions
BD = 2 AE
10 x + 2 = 2 * ( 3 x + 5 )
10 x + 2 = 6 x + 10
10 x - 6 x = 10 - 2
4 x = 8
x = 8 : 4
x = 2
And the line AC is equal to BD.
AC = 10 * 2 + 2 = 20 + 2 = 22
Answer:
3. 22
F(X) = 6/X
F(X) = 6 • 1/X
F(X) = 6 • x^-1
F(X) = 6x^-1
F'(X) = 6 • d(x^-1)/dx
F'(X) = 6 • -1x^-1-1
F'(X) = 6 • -1x^-2
F'(X) = -6x^-2
F'(X) = -6/x^2
F'(-2) = -6/(-2)^2
F'(-2) = -6/4
F'(-2) = -3/2
The solution would be C. -3/2.