All categories

3 years ago

the mass of a brick is 4 kg, find the mass of water displaced by it when completely immersed in water.

Physics

1 answer:

vova2212 [387]3 years ago

4 0

Answer:

The correct answer is = 1.6

Explanation:

Density of water = 1000kg/m³ = d₁

Mass of brick = 4kg = m

Density of brick = 2.5 g/cm³ = 2.5 × 1000 =2500 kg/m³ = d₂

Volume of brick = m/d₂ = 4/2500 =16/10000 = 0.0016 L = v

Buoyant Force = v × d₁ × g (g= acceleration due to gravity =9.8m/s²)

= 0.0016 × 1000 × 9.8 = 15.68 Newtons

By the Archimedes' Principle, the buoyant force is equal to the weight of the liquid displaced by an object.

Weight of the water displaced=Buoyant Force

=Mass of water displaced × g,

as weight = mass × acceleration due to gravity

15.68= mass of brick × 9.8

15.68/9.8 =Mass of water displaced

1.6 kg = Mass of water displaced

You might be interested in

The speed of sound in water is 1498 m/s. A sonar signal is sent straight down from a ship at a point just below the water surfac

olga2289 [7]

Answer:

The water is 1310.75 meters deep.

Explanation:

The question gives us the speed of sound and the time the sonar signal takes to travel to the bottom of the water and back.

To find out the distance, we should first divide the time in half, so we only consider the time taken for the sound to reach the bottom of the water body.

This means:

Time = 1.75 / 2 = 0.875 seconds

The distance traveled in this time is:

Distance = Speed * Time

Distance = 1498 * 0.875

Distance = 1310.75 meters

Thus, the water is 1310.75 meters deep.

8 0

4 years ago

If vector A =i+2j-k and vec A cross vec B =3i-j+5k. find vec B

postnew [5]

Let B = a i + b j + c k. Then the cross product of A = i + 2j - k with B is

A × B = ( i + 2j - k ) × ( a i + b j + c k )

A × B = a ( i × i ) + 2a ( j × i ) - a ( k × i )

… … … + b ( i × j ) + 2b ( j × j ) - b ( k × j )

… … … + c ( i × k ) + 2c ( j × k ) - c ( k × k )

A × B = 0 - 2a k - a j

… … … + b k + 0 + b i

… … … - c j + 2c i - 0

A × B = (b + 2c) i + (-a - c) j + (b - 2a) k

So we have

3 i - j + 5 k = (b + 2c) i + (c - a) j + (b - 2a) k

which gives us the system of equations,

{ b + 2c = 3

{ -a - c = -1

{ -2a + b = 5

Solve for a, b, and c.

• Eliminate c from the first two equations:

(b + 2c) + 2 (-a - c) = 3 + 2 (-1)

-2a + b = 1

But -2a + b = 5, and 5 ≠ 1, so there is no such vector B that satisfies the cross product!

8 0

3 years ago

When throwing a ball upwards, the velocity is positive, and the acceleration is negative. True of False?

Setler79 [48]

Answer:

The velocity & acceleration will be taken as negative when a ball is thrown upward because work is done against the gravity.

Explanation:

3 0

3 years ago

In most circumstances, the normal force acting on an objectand

Lynna [10]

Answer:

Normal Force is usually perpendicular to the movement and static friction usually means that there is no movement.

Explanation:

The work donde by any force on an object is equal to the displacement of the object multiplied by the component of the force that is in the direction of the displacement.

Normal force is usually perpendicular to the movement, so there is no component in the direction of the displacement. This is why it is zero in most circumstances.

Static friction on the other hand, usually means that there is no movement at all (it's static). It means that there is no displacement between the object and ground (in most cases). If there is no displacement, there is no work.

4 0

3 years ago

The illustration represents one form of _________________, the process that enables all stars, including our sun, to continuousl

jonny [76]

We have no way to say what the illustration represents, mainly because
you haven't given us a way to see the illustration.

However, the process that all stars, including our sun, use to continuously
produce energy is nuclear fusion.

8 0

4 years ago

Read 2 more answers

the mass of a brick is 4 kg, find the mass of water displaced by it when completely immersed in water.​

the mass of a brick is 4 kg, find the mass of water displaced by it when completely immersed in water.