Answer:
No, it will not and this has a historical importance. The reason is that transformers work via induction of electrical forces by changes in magnetic fields, so the constat fields produced by dc currents won't work at all
Explanation:
Answer:
Capacitive reactance is 132.6 Ω.
Explanation:
It is given that,
Capacitance, 
Voltage source, V = 20 volt
Frequency of source, f = 60 Hz
We need to find the capacitive reactance. It is defined as the reactance for a capacitor. It is given by :
So, the capacitive reactance of the capacitor is 132.6 Ω. Hence, this is the required solution.
<span>In the </span>natural logarithm<span> format or in equivalent notation (see: </span>logarithm) as:
base<span> e</span><span> assumed, is called the </span>Planck entropy<span>, </span>Boltzmann entropy<span>, Boltzmann entropy formula, or </span>Boltzmann-Planck entropy formula<span>, a </span>statistical mechanics<span>, </span><span> </span>S<span> is the </span>entropy<span> of an </span>ideal gas system<span>, </span>k<span> is the </span>Boltzmann constant<span> (ideal </span>gas constant R<span> divided by </span>Avogadro's number N<span>), and </span>W<span>, from the German Wahrscheinlichkeit (var-SHINE-leash-kite), meaning probability, often referred to as </span>multiplicity<span> (in English), is the number of “</span>states<span>” (often modeled as quantum states), or "complexions", the </span>particles<span> or </span>entities<span> of the system can be found in according to the various </span>energies<span> with which they may each be assigned; wherein the particles of the system are assumed to have uncorrelated velocities and thus abide by the </span>Boltzmann chaos assumption<span>.
I hope this helps. </span>
No. A neutron star is the weird remains of a star that blew its outer layers off
in a nova event, and then had enough mass left so that gravity crushed its
electrons into its protons, and then what was left of it shrank down to a sphere
of unimaginably dense neutron soup. But it didn't have enough mass to go
any farther than that.
A black hole is the remains of a star that had enough mass to go even farther
than that. No force in the universe was able to stop it from contracting, so it
kept contracting until its mass occupied no volume ... zero. It became even
more weird, and is composed of a substance that we don't know anything about
and can't describe, and occupies zero volume.
Contrary to popular fairy tales, a black hole doesn't reach out and "suck things in".
It's just so small (zero) that things can get very close to it. You know that gravity
gets stronger as you get closer to an object, so if the object has no size at all, you
can get really really close to it, and THAT's where the gravity gets really strong.
You may weigh, let's say, 100 pounds on the Earth. But you're like 4,000 miles
from the center of the Earth. What if all of the earth's mass was crammed into
the size of a bean. Then you could get 1 inch from it, and at that distance from
the mass of the Earth, you would weigh 25,344,000,000 pounds.
But Earth's mass is not enough to make a black hole. That takes a minimum
of about 3 times the mass of the sun, which is right about 1 million times the
Earth's mass. THEN you can get a lightweight black hole.
Do you see how it works now ?
I know. It all seems too fantastic to be true.
It sure does.
Answer:
a
b
Horizontal component
vertical component
c
d
Explanation:
Generally from the question we can deduce that he initial velocity of the cork, as seen by an observer on the ground in terms of the x unit vector is
due to the fact that the cork is moving horizontally
Generally from the question we can deduce that the vertical and horizontal components of the initial velocity is
due to the fact that the balloon is moving downward which is the negative which will also cause the cork to move vertically with the balloon speed
Generally the initial velocity (magnitude and direction) of the cork, as seen by an observer on the ground is mathematically represented as
Generally the initial direction of motion as seen by the same observer is mathematically represented as
![\theta = tan^{-1}[\frac{2}{5} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20tan%5E%7B-1%7D%5B%5Cfrac%7B2%7D%7B5%7D%20%5D)
Generally the time taken by the cork in the air before landing is mathematically represented as
So D = 6 \ m from the question
g = 9.8 \ m/s^2
u = 
= 2 m/s this because we are considering the vertical motion
So
Solving using quadratic formula w have that
Generally the distance of the cork from the balloon is mathematically represented as
