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Elenna [48]
2 years ago
13

What is the difference between a sonic boom and a shock wave?

Physics
1 answer:
WINSTONCH [101]2 years ago
3 0

Answer:

When a sound source moves faster than the speed of sound, a shock wave is produced as the sound waves interfere. A sonic boom is the intense sound that occurs as the shock wave moves along the ground.

More importantly, all of the energy gets concentrated into a very small distance this is called a shock wave. In this case, the observer does not hear the approaching source at all until the shock wave hits with all of the energy in the wave. For sound waves, this can cause a very loud noise, called a sonic boom.

Sonic booms produced by aircraft flying supersonic at altitudes of less than 100 feet, creating between 20 and 144 pounds overpressure, have been experienced by humans without injury. Damage to eardrums can be expected when overpres- sures reach 720 pounds

Explanation:

marke as brainliest

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I1*ω1 = I2*ω2 -----> I1*ω1/I2 = 129*95/32 = 383 RPM <<<<<

383 rev/min * 2πrad/rev * 1min/60s = 383*2π/60 = 40.1 radians/s <<<

3 0
3 years ago
A variação no comprimento de uma barra de alumínio foi de 0,0002m. Calcular a variação na temperatura a =22x10-⁶
Furkat [3]

Answer:

1.82°C

Explanation:

presumir inicial comprimento = l₀ = 5 m

dado que:

coeficiente de expansão (α) = 22 x 10⁻⁶, A variação no comprimento (ΔL) = 0.0002 m,

inicial comprimento = l₀ = 5 m

variação na temperatura = ΔT

para Calcular a variação na temperatura,  nós usamos a fórmula:

\Delta L=l_0\alpha \Delta T

substituindo valores:

0.0002=5*22*10^{-6}\Delta T\\\Delta T=\frac{0.0002}{5*22*10^{-6}}\\ 5*22*10^{-6}=1.82^0C

variação na temperatura = 1.82°C

8 0
3 years ago
The moving charge in the wire causes the compass to deflect; this is because
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The answer is A. the moving charge induces a magnet field .


5 0
3 years ago
Read 2 more answers
A device for acclimating military pilots to the high accelerations they must experience consists of a horizontal beam that rotat
vladimir2022 [97]

Answer:

f = 0.4 Hz

Explanation:

The frequency of rotation of an object in order to achieve required centripetal or radial acceleration, can be found out by using the following formula:

f = (1/2π)√(ac/r)

where,

f = frequency of rotation = ?

ac = radial acceleration = 34.1 m/s²

r = radius = length of beam = 5.55 m

Therefore,

f = (1/2π)√[(34.1 m/s²)/(5.55 m)]

<u>f = 0.4 Hz</u>

6 0
3 years ago
A ball of 0.5kg slows down from 5m/s to 3m/s. Calculate the work done inthe process.
dlinn [17]

Answer:

9.8 Joules (rounded to 2 significant figures)

Explanation:

Work done (J)= Force(N) x distance changed (m)

  • Force= 9.80665 x 0.5kg
  • Force= 4.90332 Newtons

  • Distance changed= 5-3
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--> work done= 4.90332 x 2

work done= 9.8 Joules

5 0
3 years ago
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