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2 years ago

13

What is the difference between a sonic boom and a shock wave?

1 answer:

WINSTONCH [101]2 years ago

3 0

Answer:

When a sound source moves faster than the speed of sound, a shock wave is produced as the sound waves interfere. A sonic boom is the intense sound that occurs as the shock wave moves along the ground.

More importantly, all of the energy gets concentrated into a very small distance this is called a shock wave. In this case, the observer does not hear the approaching source at all until the shock wave hits with all of the energy in the wave. For sound waves, this can cause a very loud noise, called a sonic boom.

Sonic booms produced by aircraft flying supersonic at altitudes of less than 100 feet, creating between 20 and 144 pounds overpressure, have been experienced by humans without injury. Damage to eardrums can be expected when overpres- sures reach 720 pounds

Explanation:

marke as brainliest

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A weightlifter completes a series of lifts with a 700 N weight. In one lift, he raises the weight to a height of 2.5 m off the g

zhannawk [14.2K]

Answer:

The output power the weightlifter is 2916.67 W.

Explanation:

Given;

weight lifted, W = 700 N

height the weight is lifted, h = 2.5 m

time taken to lift the weight, t = 0.60 s

The output power the weightlifter is calculated as;

Power = Energy applied / time taken

Energy applied = weight lifted x height the weight is lifted

Energy applied = 700 x 2.5

Energy applied = 1750 J

Power = 1750 / 0.6

Power = 2916.67 J/s = 2916.67 W.

Therefore, the output power the weightlifter is 2916.67 W.

5 0

2 years ago

In Example 2.12, two circus performers rehearse a trick in which a ball and a dart collide. Horatio stands on a platform 6.4 m a

pickupchik [31]

Answer:

time of collision is

t = 0.395 s

$h = 5.63 m$

so they will collide at height of 5.63 m from ground

Explanation:

initial speed of the ball when it is dropped down is

$v_1 = 0$

similarly initial speed of the object which is projected by spring is given as

$v_2 = 16.2 m/s$

now relative velocity of object with respect to ball

$v_r = 16.2 m/s$

now since we know that both are moving under gravity so their relative acceleration is ZERO and the relative distance between them is 6.4 m

$d = v_r t$

$6.4 = 16.2 t$

$t = 0.395 m$

Now the height attained by the object in the same time is given as

$h = v_2 t - \frac{1}{2}gt^2$

$h = 16.2(0.395) - \frac{1}{2}(9.81).395^2$

$h = 5.63 m$

so they will collide at height of 5.63 m from ground

4 0

3 years ago

You are a traffic accident investigator. You have arrived at the scene of an accident. Two cars of equal mass (1,000 kg each) we

kumpel [21]

6. Is 50 m/s that’s the answer

4 0

2 years ago

một động cơ nhiệt khi hoạt động nhiệt lượng mà nó nhận vào gấp bốn lần công mà nó thực hiện. Hiệu suất của động cơ là?

OlgaM077 [116]

$\frac{1}{4} = 0.25 = 25\%$

6 0

2 years ago

A 6.00-mH solenoid is connected in series with a 5.0-μF capacitor and an AC source. The solenoid has internal resistance 3.0 Ω w

son4ous [18]

Answer:

5773.50269 Hz

23 A

Explanation:

$L$ = Inductance = 6 mH

$C$ = Capacitance = 5 μF

$R$ = Resistance = 3 Ω

$\epsilon$ = Maximum emf = 69 V

Resonant angular frequency is given by

$\omega=\dfrac{1}{\sqrt{LC}}\\\Rightarrow \omega=\dfrac{1}{\sqrt{6\times 10^{-3}\times 5\times 10^{-6}}}\\\Rightarrow \omega=5773.50269\ Hz$

The resonant angular frequency is 5773.50269 Hz

Current is given by

$I=\dfrac{\epsilon}{R}\\\Rightarrow I=\dfrac{69}{3}\\\Rightarrow I=23\ A$

The current amplitude at the resonant angular frequency is 23 A

7 0

2 years ago