Answer:
U = 80.91 J
Explanation:
In order to calculate the electric potential energy between the three charges you use the following formula:
(1)
k: Coulomb's constant = 8.98*10^9Nm^2/C^2
q1: q2 charge
r1,2: distance between charges 1 and 2.
For the three charges you have:
(2)
You use the fact that q1=q2=q3=q and that the distance between charges are equal. Then, in the equation (2) you have:
q = 1.45μC = 1.45*10^-6C
r = 0.700mm = 0.700*10^-3m

The electric potential energy between the three charges is 80.91 J
Answer:
<u><em>note:</em></u>
<u><em>solution is attached due to error in mathematical equation. please find the attachment</em></u>
Answer:
The current would be same in both situation.
Explanation:
Given that,
Current I = 13 A
Number of turns = 23
We need to calculate the induced emf
Using formula of induced emf is

For N = 1

We need to calculate the current
Using formula of current

Put the value of emf

Now, if the number of turn is 22 , then induced emf would be

Then the current would be




Hence, The current would be same in both situation.
P = IV
I = P/V = 30 / 120 = 0.25 A.
Current = 0.25A