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3 years ago

9

You are going to an outdoor concert, and you'll be standing near a speaker that emits 60 W of acoustic power as a spherical wave

. What minimum distance should you be from the speaker to keep the sound intensity level below 94 dB?

1 answer:

Bas_tet [7]3 years ago

3 0

Answer:

$r=44m$

Explanation:

β is calculated as:

$\beta =(10dB)log_{10}(I/I_{o} )\\ I=I_{o}10^{\frac{\beta }{10dB} }\\ I=(1.0*10^{-12}W/m^{2} )10^{\frac{\(94dB }{10dB} }\\I=2.51mW/m^{2}$

The distance r is defined as the radius of spherical wave.solve for r

We have

$I=\frac{P_{source} }{4\pi r^{2} }\\ r=\sqrt{\frac{P_{source}}{4\pi I} }\\ r=\sqrt{\frac{60W}{4\pi (2.51mW/m^{2} )} }\\r=44m$

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Explanation:

Expression to calculate thermal resistance for iron ( $R_{I}$ ) is as follows.

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where, $L_{I}$ = length of the iron bar

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$A_{I}$ = Area of cross-section for the iron bar

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Now, expression for the transfer of heat per unit cell is as follows.

Q = $\frac{(100^{o} - 0^{o}}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}$

Putting the given values into the above formula as follows.

Q = $\frac{(100^{o} - 0^{o})}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}$

= $\frac{(100^{o} - 0^{o})}{21 \times 10^{-2} m[\frac{1}{73 \times 10^{-4}m^{2}} + \frac{1}{386 \times 10^{-4}m^{2}}}$

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3 years ago

g If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resi

Anettt [7]

<h2>Question:</h2>

In this circuit the resistance R1 is 3Ω, R2 is 7Ω, and R3 is 7Ω. If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resistance be?

Answer:

9.1Ω

Explanation:

The circuit diagram has been attached to this response.

(i) From the diagram, resistors R1 and R2 are connected in parallel to each other. The reciprocal of their equivalent resistance, say Rₓ, is the sum of the reciprocals of the resistances of each of them. i.e

$\frac{1}{R_X} = \frac{1}{R_1} + \frac{1}{R_2}$

=> $R_{X} = \frac{R_1 * R_2}{R_1 + R_2}$ ------------(i)

From the question;

R1 = 3Ω,

R2 = 7Ω

Substitute these values into equation (i) as follows;

$R_{X} = \frac{3 * 7}{3 + 7}$

$R_{X} = \frac{21}{10}$

$R_{X} = 2.1$ Ω

(ii) Now, since we have found the equivalent resistance (Rₓ) of R1 and R2, this resistance (Rₓ) is in series with the third resistor. i.e Rₓ and R3 are connected in series. This is shown in the second image attached to this response.

Because these resistors are connected in series, they can be replaced by a single resistor with an equivalent resistance R. Where R is the sum of the resistances of the two resistors: Rₓ and R3. i.e

R = Rₓ + R3

Rₓ = 2.1Ω

R3 = 7Ω

=> R = 2.1Ω + 7Ω = 9.1Ω

Therefore, the combination of the resistors R1, R2 and R3 can be replaced with a single resistor with an equivalent resistance of 9.1Ω

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