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alexandr1967 [171]
4 years ago
6

I don’t know how to start with drawing the diagram for this question.

Mathematics
1 answer:
kogti [31]4 years ago
6 0

Consider right triangles ADB and ADC in the figure, right angle D.

By alternate transversals ABD=63° and ACD=11°.

\tan 63 = \dfrac 8 y

\tan 11 = \dfrac 8{x+y}

y = \dfrac{8}{\tan 63}

x = -y +  \dfrac{8}{\tan 11}

x = \dfrac{8}{\tan 11} -  \dfrac{8}{\tan 63}

x \approx 37.08 \textrm{ meters}

That's in one second, so

Answer: 37 meters per second

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Elena-2011 [213]

Answer:

CDE=50 degrees ACD=100,BAC=30 degrees.

6 0
3 years ago
Determine the number of solutions for the system of equations. 1. { y=2/5x^2, y=x-2. 2. {y=3x^2, y-3x=-2
umka2103 [35]

A system of two equations can be classified as follows: If the slopes are the same but the y-intercepts are different, the system has no solution. If the slopes are different, the system has one solution. If the slopes are the same and the y-intercepts are the same, the system has infinitely many solutions.

4 0
3 years ago
Plz answer very urgent​
Tcecarenko [31]
<h2><em>Answer:</em></h2><h2><em>1</em><em>.</em><em>0</em><em>6</em></h2>

<em>Solution</em><em>,</em>

<em>9</em><em>x</em><em>/</em><em>7</em><em>-</em><em>6</em><em>x</em><em>=</em><em>1</em><em>5</em>

<em>or,</em><em>9</em><em>x</em><em>=</em><em>1</em><em>5</em><em>(</em><em>7</em><em>-</em><em>6</em><em>x</em><em>)</em><em>[</em><em> </em><em>cross </em><em>multiplication]</em>

<em>or,</em><em>9</em><em>x</em><em>=</em><em>1</em><em>0</em><em>5</em><em>-</em><em>9</em><em>0</em><em>x</em>

<em>or,</em><em>9</em><em>x</em><em>+</em><em>9</em><em>0</em><em>x</em><em>=</em><em>1</em><em>0</em><em>5</em>

<em>or,</em><em>9</em><em>9</em><em>x</em><em>=</em><em>1</em><em>0</em><em>5</em>

<em>or,</em><em>X=</em><em>1</em><em>0</em><em>5</em><em>/</em><em>9</em>

<em>X=</em><em>1</em><em>.</em><em>0</em><em>6</em>

<em>Hope </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

5 0
4 years ago
Fatima divided 63 by 9 and got a quotient of 6. is she correct? explain.
allsm [11]
No she is not correct . 63 divided by 9 is 7 not 6 
5 0
3 years ago
Quadrilateral ABCD has vertices at A(0,6), (4,-1), c(-4,0) and d(-8,7). prove that:
MakcuM [25]

Answer:

Step-by-step explanation:

8 0
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