Answer:
Explanation:
Given
Person on earth can jump to a height
initial velocity is u
using
where v=final velocity
u=initial velocity
a=acceleration
s=displacement
final velocity is zero
On moon surface acceleration due to gravity is \frac{1}{6}[/tex] th of earth gravity
so height attained is given by
divide 1 and 2 we get
Answer:
Hey Queen Messy here!
I believe it is true.
Weight is the way we usually describe what the scales tell us, but our weight is actually something different.
"When you get on the scale and it tells you that you weigh 50 kilograms, that isn't your weight. That's actually your mass", says Dr Nicole Bell from the University of Melbourne.
"In everyday speech weight and mass are used interchangeably, but weight is a figure arrived at by multiplying mass by gravitational acceleration".
Physicists use Newton's 2nd law (F = ma) to describe the forces acting upon an object moving through space, where force is equal to mass times acceleration.
"In the case of weight, we can describe the force as W = mg", says Bell. "That is weight is equal to mass times gravitational acceleration.
Weight is not measured in kilograms, but in Newtons.
Explanation:
Answer:
Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.
Explanation:
hint
Answer:
<em>The</em><em> cliff is 74.4m</em>.
Explanation:
<em>The</em><em> </em><em>reading</em><em> </em><em>above</em><em> </em><em>clearly</em><em> state</em><em> </em><em>that</em><em> </em><em>a</em><em> </em><em>ball </em><em>is </em><em>dropped</em><em> </em><em>straight</em><em> </em><em>down</em><em> </em><em>with</em><em> </em><em> the</em><em> </em><em>speed</em><em> of</em><em> </em><em>9</em><em>.</em><em>3</em><em>m</em><em>/</em><em>s </em><em>and</em><em> </em><em>hit </em><em>the</em><em> </em><em>ground</em><em> </em><em>exactly</em><em> </em><em>at </em><em>a </em><em>time</em><em> of</em><em> </em><em>8</em><em>.</em><em>0</em><em>s</em><em> </em><em>after</em><em> </em><em>you</em><em> </em><em>released</em><em> it</em><em>.</em><em> </em><em>And </em><em>it</em><em> </em><em>is </em><em> </em><em>asking </em><em>for</em><em> the</em><em> </em><em>distance</em><em> of</em><em> the</em><em> </em><em>cliff</em><em>.</em>
<em>In </em><em>speed</em><em> formula</em><em> </em><em>make</em><em> </em><em>distance</em><em> the</em><em> </em><em>subject.</em>
<em>Therefore</em><em> </em><em>Distance</em><em> </em><em>=</em><em> </em><em>speed</em><em> </em><em>×</em><em> </em><em>time</em>
<em>Distance</em><em> </em><em>=</em><em> </em><em>9</em><em>.</em><em>3</em><em>m</em><em>l</em><em>s</em><em> </em><em>×</em><em> </em><em>8</em><em>.</em><em>0</em><em>s</em><em> </em><em>=</em><em> </em><em>7</em><em>4</em><em>.</em><em>4</em><em>m</em>
<em>Therefore</em><em> the</em><em> </em><em>c</em><em>l</em><em>i</em><em>f</em><em>f </em><em>is </em><em>7</em><em>4</em><em>.</em><em>4</em><em>m</em><em>.</em>
Answer:
mass of second ball is 0.84 kg
Explanation:
mass of ball = 0.280 kg
to find out
mass of the second ball
solution
we know here elastic head on collision and
second ball moves = half the original speed
we consider here m1 mass of 1st ball and m2 mass of second ball
v1 = velocity of first ball before collision
v2 = velocity of second ball before collision
v3 = velocity of first ball after collision
v4 = velocity of second ball after collision
so here
we know 2nd ball was on rest so v2 = 0
after collision v4 = 1/2 ( v1)
and we know head on collision so
v3 = - v1/2
so from law of conservation of mass
m1v1 + m2v2 = m1v3 + m2v4
put here value
m1v1 + m2(0) = m1(-v1/2) + m2(v1/2)
solve and we get
m2 = 3m1
m2 = 3( 0.280) = 0.84
mass of second ball is 0.84 kg