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ivolga24 [154]
3 years ago
7

What activity would require more impulse?

Physics
1 answer:
Gnesinka [82]3 years ago
3 0

B. Accelerating a bowling ball from rest to 35 m/s

Explanation:

Accelerating a bowling ball from rest to 35m/s will require more impulse compared to a baseball.

Impulse is the force acting on a body a particular period of time. It is similar to momentum.

When impulse is applied on a body, it change it state from rest and cause motion.

A body with more mass will require a higher impulse to cause it to accelerate. Bowling balls are heavier. They require more impulse to make them move.

Learn more:

Momentum brainly.com/question/9484203

#learnwithBrainly

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Give an example for each of the following, where the force:
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Explanation:

  • A cricket player hitting the ball from opposite direction.
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  • Applying brake of a car.
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Elena puts her eggs in a cage made out of wood. The wood breaks during
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A long wire carrying a 5.0 A current perpendicular to the (xy)-plane intersects the x-axis at x = -2.00 cm. A second parallel wi
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Answer:

a. 05cm from x axis

b. 8cm from x axis

Explanation:

If the net magnetic field is zero and the currents are in the same direction then the thanks point is between the currents i1 and i2 as show in the attachment below

a. Given that i1= 5A and i2=3A

Let assume the null point is xcm from current i1, then the null point will be (4-x)cm from current i2 since the total length is 4cm.

Now the magnetic field of the current i1 from the null point= to magnetic field of current i2 from the null point

B1=B2

μi1/2πx=μi2/2π(4-x)

i1/x=i2/(4-x)

5/x=3/(4-x)

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8x=20

8x=2.5cm

since from the left of x axis is 2cm, then the null point is 2.5-2 which 0.5cm from the origin x axis.

The null point is 0.5cm from the origin x axis

b. If both current are flowing in opposite direction, the null point lies outside of the current.

Then with same analysis let assume the first current i1 is xcm from the null point and since the total length is 4cm the second current i2 will be (x-4)cm from the null point.

Also the magnetic field of the current i1 from the null point = to magnetic field of current i2 from the null point

B1=B2

μi1/2πx=μi2/2π(x-4)

i1/x=i2/(x-4)

5/x=3/(x-4)

5x-20=3x

2x=20

x=10cm.

This shows that the distance of the null point from current i1 is 10cm and the current i1 is 2cm from the x axis, then the null point is 10-2=8cm from the origin x axis.

The null point is 8cm from the x axis.

Check the attachment to see the diagram of the current and the null points

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