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sineoko [7]
3 years ago
6

Global winds move warm air toward the _____.

Physics
2 answers:
Bezzdna [24]3 years ago
5 0

global winds move warm air toward the poles

Taya2010 [7]3 years ago
3 0

Explanation:

It is known that equator lies near the Sun as the globe or Earth revolves around the Sun. Therefore, air near the region of equator is warm due to the heat coming from the Sun.

As a result, this warm air rises towards the poles as warmth from the Sun helps the air molecules to gain kinetic energy and therefore, they move towards the pole which is a colder region as compared to the equator.

Therefore, we can conclude that global winds move warm air toward the pole.

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Two positive point charges, each of which has a charge of 2.5 × 10−9 C, are located at y = + 0.50m and y = − 0.50m. Find the mag
Salsk061 [2.6K]

Answer:

The resultant electric force is 14.8N to the right.

Explanation:

Since the three charges aren't in the same line, we have to break down the force in components. First, we need to know the distance from the third charge to the other ones. That is made using the Pythagorean Theorem. As the figure is symmetric with respect to the x-axis, the two distances are the same:

r=\sqrt{(0.50m)^{2}+(0.70m)^{2}}=0.86m

Now, we use the Coulomb's Law to obtain the magnitude of the individual forces caused by each charge on the third charge:

|F_{13}|=k\frac{q_1q_3}{r^{2}} \\\\|F_{13}|=(9*10^{9}Nm^{2}/C^{2})\frac{(2.5*10^{-9}C)(3.0*10^{-9}C)}{(0.86m)^{2}}\\\\|F_{13}|=9.1N

For the same reason the distances are the same, the magnitude of the forces are the same:

|F_{23}|=|F_{13}|=9.1N

So, to get the resultant force, we have to break down this forces in components. To do this, we need their angles with respect to the x-axis. Let θ₁ and θ₂ be these angles, respectively. Then, we calculate them using trigonometry:

\theta_1=\arctan(\frac{-0.50m}{0.70m})=-35.5\°\\\\\theta_2=\arctan(\frac{0.50m}{0.70m})=35.5\°

Now, we calculate the components of the forces:

F_{13}_x=F_{13}\cos\theta_1=9.1N\cos(-35.5\°)=7.4N\\\\F_{13}_y=F_{13}\sin\theta_1=9.1N\sin(-35.5\°)=-5.3N\\\\F_{23}_x=F_{23}\cos\theta_2=9.1N\cos(35.5\°)=7.4N\\\\F_{23}_y=F_{23}\sin\theta_2=9.1N\sin(35.5\°)=5.3N

Evidently, the y-components cancel out, and the resultant electric force on the third charge is 7.4N+7.4N=14.8N along the x-axis (to the right, because it's positive).

8 0
3 years ago
Sergei tees off on a stationary hockey puck using his most powerful slap shot. If he can exert a force of 250 N on the 500 gram
ASHA 777 [7]

Answer: velocity = 50m/s

Distance moved=5m

Explanation:

Using the formula Ft=Mv i.e impulse= momentum

Where F= force ,t= time, M= mass, v = velocity

In this case we need to find v,

F,t,M are all given in the question.

Therefore, substituting the values we have

250N×0.1s=0.5kg×v. Mass=500g= 0.5kg

v=25/0.5= 50m/s

The distance the puck will move when it is on his stick.

D= Velocity × time

D=50m/s × 0.1s

D=5m

Goodluck...

8 0
3 years ago
Is orange juice in an orange potential energy or kinetic energy?
kicyunya [14]
It would be potential energy because it is not moving. <span />
3 0
4 years ago
Read 2 more answers
1. The weight of body in air is 20N displaced 5N when emerged into water. The mass of body in water is ??​
marishachu [46]

Answer:

5 N

Explanation:

Archimedes' principle indicates that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.

In this case, The weight of an object in air is 20N and it weighs x N when fully immersed in water. So, the weight of the water displaced is given as;

20 − x = 5

Therefore, the weight of the body in water is 5 N.

4 0
1 year ago
A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much work was done?
jeka57 [31]

Answer:

<h3>The answer is 45 J</h3>

Explanation:

The work done by an object can be found by using the formula

<h3>workdone = force × distance</h3>

From the question

distance = 3 meters

force = 15 newtons

We have

workdone = 15 × 3

We have the final answer as

<h3>45 J</h3>

Hope this helps you

7 0
3 years ago
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