Answer:
0.25%
Explanation:
20 people start the new population. So there are 20 genes or 40 alleles for the recessive disorder phenylketonuria. 2 out of 40 alleles are recessive for the condition hence frequency of the allele = 2/40 = 0.05
Frequency of the allele does not change when the population increases so it is in Hardy-Weinberg equilibrium. According to it, if q is the frequency of recessive allele, q² = frequency of the recessive condition
Here, q = 0.05 So,
q² = (0.05)² = 0.0025
In percentage, it is 100 * 0.0025 = 0.25%
Hence, incidence of phenylketonuria in the new population is 0.25%
The amount of glucose in each ml of their blood will be 0.00138 g.
<h3>Blood glucose concentration</h3>
The concentration of glucose in the person's blood is 1.38%.
This means that there is 1.38 g of sugar per Liter of blood.
1 Liter of blood contains 1.38 g of glucose, and there is 1000 mL in 1 Liter of blood.
1000 mL contains 1.38 g
1 ml contains = 1.38 x 1 / 1000 = 0.00138 g
This means 0.00138 g of glucose will be present in every 1 mL of the person's blood.
More on blood glucose can be found here: brainly.com/question/8394646
#SPJ1
natural selection, bc it is the process whereby organisms better adapted to their environment tend to survive and produce more offspring
That's false, it's the pons :)
