Answer:
it's too blurryyyyyyyyyyyyyyyyyyyyy
For this case , the parent function is given by [tex f (x) =x^2
[\tex]
We apply the following transformations
Vertical translations :
Suppose that k > 0
To graph y=f(x)+k, move the graph of k units upwards
For k=9
We have
[tex]h(x)=x^2+9
[\tex]
Horizontal translation
Suppose that h>0
To graph y=f(x-h) , move the graph of h units to the right
For h=4 we have :
[tex ] g (x) =(x-4) ^ 2+9
[\tex]
Answer :
The function g(x) is given by
G(x) =(x-4)2 +9
No he is not, 10*0.13=1.3, so 5*0.13=0.65
Answer:
p = 8
Step-by-step explanation:
Answer:
Very last choice is the answer.
Step-by-step explanation:
Remark
The thing that is most important is that the horizontal line connect h and the radius is parallel to the cut of the sphere if it was placed right in the middle. That line swings around as though the center was a pivot.
Solution
- So what you have is a circle when that line goes around that part of the sphere.
- To find the length of that line, use the Pythagorean Theorem. Call the line r1.
- r1 ^2 = r^2 - h^2
- So the area is pi * r1^2
- Area = pi (r^2 - h^2)
- The very last one is the answer.
