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zmey [24]
3 years ago
9

How many molecules are there in 4.00 l of oxygen gas at 500.∘ c and 50.0 torr?

Chemistry
1 answer:
Oliga [24]3 years ago
3 0
From  the  ideal  gas law   
pv=nRT , n  is  therefore PV/RT
R is  the
R is  gas  constant =62.364 torr/mol/k
P=500torr
 V=4.00l
T=500+273=773k
n={(500 torr x 4.00l)/(62.364 x773k)}=0.041moles
the  number  of  molecules=moles  x avorgadro costant that is  6.022x10^23)
6.022 x 10^23)  x0.041=2.469 x10^22molecules
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Question 43 please. i’m not sure if i got the right answer
hram777 [196]

a) The reaction is exothermic since the overall enthalpy change is negative. this means that the system has lost energy to the environment, namely, the apparatus and due to drought.

b) We first calculate the number of moles in 3.55 grams of magnesium.

number of moles= mass/ atomic mass

                            =3.55/24

                            =0.1479 moles(to 4sf)

now, if 2 moles of magnesium give -1204kJ

        How much energy is given by 0.1479 moles

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c) two molesof MgO produces -1204kJ of energy

then -234kJ will be produced by

=(-234kJ×2moles)/1204kJ

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therefore the mass produced is 0.3887moles×40=15.548grams

(d) we first find the number of moles of MgO in 40.3 grams

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if 2 moles of MgO give 1204 kJ then decomposing 1.0075 moles requires

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3 years ago
An expandable container of oxygen has a volume of 30.0mL at a pressure of 36.7psi. If the pressure of the oxygen is reduced to 2
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Answer:44.04mL

Explanation:Parameters given

V1 = 30.0mL

P1 = 36.7psi

P2 = 25.0psi

V2 = ??

From Boyle's gas law, which states that "the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature"

This means that,

the pressure of a gas tends to increase as the volume of the container decreases, and also the pressure of a gas tends to decrease as the volume of the container increases.

Mathematically, Boyle's can be represented as shown below

P= k/V

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Therefore,

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P1V1 = P2V2 =PnVn

Using the formula

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V2 = P1V1/P2

V2 = (36.7psi × 30.0mL) / 25.0psi

V2 = 1101.0/25.0

V2 = 44.04mL

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3 years ago
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