Answer:
the answer is v and z. you can see the pic
The density of ethylene glycol is: D = 1.11 g/mL
D = m / V
and V = 358 mL
m = D * V
m = 1.11 g/mL * 358 mL
m = 397.38 g
Answer:
Mass is 397.38 g.
Limiting reactant : O₂
Mass of N₂O₄ produced = 95.83 g
<h3>Further explanation</h3>
Given
50g nitrous oxide
50g oxygen
Reaction
2N20 + 302 - 2N204
Required
Limiting reactant
mass of N204 produced
Solution
mol N₂O :

mol O₂ :

2N₂O+3O₂⇒ 2N₂O₄
ICE method
1.136 1.5625
1.0416 1.5625 1.0416
0.0944 0 1.0416
Limiting reactant : Oxygen-O₂
Mass N₂O₄(MW=92 g/mol) :
