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Anna71 [15]
1 year ago
6

Who is the atom from the other end of town?

Chemistry
1 answer:
Yanka [14]1 year ago
7 0

Answer:

The Atom is a superhero character from DC Comics. He is a founding member of the Justice League and possesses the ability to shrink himself to subatomic size. In the comics, he is Ray Palmer, a scientist from Ivy Town.

Explanation:

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There are two isotopes of an unknown element, X-19 and X-21. The abundance of X-19 is 14.55%. A weighted average uses the percen
alekssr [168]

Answer:

2.765amu is the contribution of the X-19 isotope to the weighted average

Explanation:

The average molar mass is defined as the sum of the molar mass of each isotope times its abundance. For the unknown element X that has 2 isotopes the weighted average is defined as:

X = Mass X-19 * Abundance X-19 + MassX-21 * Abundance X-21

The contribution of the X-19 isotope is its mass (19.00 amu) times its abundance (14.55% = 0.1455). That is:

19.00amu * 0.1455 =

2.765amu is the contribution of the X-19 isotope to the weighted average

8 0
3 years ago
1. How is the law of conservation of mass shown by a balanced chemical equation?
Ilia_Sergeevich [38]

Answer:

D

Explanation:

hope this helps

3 0
3 years ago
at 55 years what mass remains of a 200.0 g sample of a radioactive isotope with a half life of 10.0 years
Harman [31]

Answer:

4.419 g

Explanation:

     55 years is 5.5 half lives

200 g   *   (1/2)^5.5 = 4.419 g

3 0
1 year ago
What type of energy is this and why?
Murljashka [212]

Answer:

I make not know because im the 7th grade but Im give my worthy guess  I now this its endothermic

Explanation:

4 0
3 years ago
324.55 cm - (6104.5 cm²/22.3 cm)
Ganezh [65]

Answer: 50.806 cm is the correct answer.

Explanation: First divide 6104.5 cm^2 by 22.3 cm.

\frac{6104.5cm^2}{22.3cm} = 273.74 cm

*Note: When dividing units, subtract the exponents, and when multiplying units simply add the exponents.

Then continue by subtracting 324.55 cm - 273.74 cm.

This should give you an answer of 50.806 cm.

3 0
2 years ago
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