Answer:
4.15g
Explanation:
Balance the reaction:
2Mg + O2 = 2MgO
Find limiting reactant from the two, by dividing miles with coefficient
2.5/24.3 = 0.103 moles/2 = 0.0515
5/16 = 0.31 moles/2 = 0.156
0.0515 is small than 0.156, so limiting reactant is Mg
Compare the ratio of Mg with MgO
Ratio is 2:2
So same moles = 0.103 moles
Mass = moles x molar mass of MgO
Mass = 0.103 x 40.3
= 4.15g
*please give brainlest*
Lar mass of Ca<span> = 40.08 </span>grams/mole 77.4 g Ca<span> * ( 1 </span>mole Ca<span>/ 40.08 ... n = m / M 1mol </span>Ca<span>weights 40 gmol-1 n = 77,4 / 40 = 1.93 </span>mol<span>.</span>
During this process. A. Solid turns directly into a Gas.
Answer:
No.
Explanation:
No. There is 1 atom of Ca on the left and 2 Ca's on the right and 2 OH's on the left and 4 on the right.
The balanced equation is:
4OH- + 2Ca2+ ----> 2Ca(OH)2.
