Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
Answer:
43°
Step-by-step explanation:
Calculating for the measure of angle C using
<h3>sine rule</h3>
Answer:
<BAC=19
Step-by-step explanation:
<AOB=<DOC=142
<BAC=<ABD
2<BAC=180-142
2<BAC=38
<BAC=38/2
<BAC=19
We have a line passing through 3 points. We can use the first
two points to find the equation of the line.
(6,3), (8,4)
slope m = (4-3)/(8-6) = 1/2
We can use the point slope form y-y1 = m(x-x1) or
the slope intercept form y = mx + b
to find the equation of the line.
Let's take the point (6,3) and use y = mx + b to find b
y = 3, x = 6, m = 1/2
3 = (1/2)(6) + b
3 = 3 + b
0 = b
The equation of our line is y = (1/2)x
We have a line of equation y = (1/2)x going through point (n,-2)
Plugging in we have: -2 = (1/2)n
2(-2) = n
-4 = n
Your answer is n = -4
NOTE: looking at the 3 points as given initially: (6,3), (8,4), (n,-2)
We can see that 3 = (1/2)6 and 4 = (1/2)8 so -2 = (1/2)n makes sense
Hope this helps you :)
