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Masteriza [31]
4 years ago
15

How do I convert 498.82 cg to mg

Physics
2 answers:
disa [49]4 years ago
5 0

<h2>498.82 cg = 4988.2 mg</h2>

<h3>Further explanation</h3>

Some units of length and its conversion that need to be recalled are:

1 ~ foot = 30.48 ~ cm

1 ~ inch = 2.54 ~ cm

1 ~ foot = 12 ~ inches

1 ~ mile = 1609.34 ~ metres

1 ~ yard = 0,9144 ~ metres

1 ~\mu m = 1 \times 10^{-6} ~ m

Let us now tackle the problem!

This problem is about conversion of units of mass.

\boxed {1 ~ cg = 10 ~ mg}

498.82 ~ cg = 498.82 \times 10 ~ mg

\large {\boxed {498.82 ~ cg = 4988.2 ~ mg} }

Another example of conversion:

498.82 ~ cg = 49.882 ~ dg

498.82 ~ cg = 4.9882 ~ g

498.82 ~ cg = 0.49882 ~ dag

498.82 ~ cg = 0.049882 ~ hg

498.82 ~ cg = 0.0049882 ~ kg

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302
  • Conversion Factor : brainly.com/question/555814
  • Convert to Square Metres : brainly.com/question/2088305
  • Speed of The Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Physical Quantities

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Length , Mass , Physical , Quantities , Conversion , Unit , cg , mg , kg

mezya [45]4 years ago
3 0
<span><u><em>Answer:</em></u>
498.82 cg is equivalent to 4988.2 mg

<u><em>Explanation:</em></u>
cg stands form centigrams
mg stands for milligrams

From the standards of conversion, to convert from centi to milli, we multiply the amount ny 10

<u>This means that:</u>
1 centigram = 10 milligram

To convert 498.82 cg to mg, all we have to do is <u>cross multiplication</u> as follows:
1 cg ..................> 10 mg
498.82 cg .........> ?? mg

498.82 cg = </span>\frac{498.82*10}{1}<span> = 4988.2 mg

Hope this helps :)</span>
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4 0
3 years ago
the average american receives 2.28 mSv dose equivalent from radon each year. Assuming you receive this dose, and it all comes fr
Dmitry [639]

Answer:

The approximate number of decays  this represent  is  N= 23*10^{10}  

Explanation:

 From the question we are told that

    The amount of Radiation received by an average american is I_a = 2.28 \ mSv

     The source of the radiation is S = 5.49 MeV \ alpha \ particle

 Generally

            1 \  J/kg = 1000 mSv

   Therefore  2.28 \ mSv = \frac{2.28}{1000} = 2.28 *10^{-3} J/kg

Also  1eV = 1.602 *10^{-19}J

  Therefore  2.28*10^{-3} \frac{J}{kg} = 2.28*10^{-3} \frac{J}{kg}  * \frac{1ev}{1.602*10^{-19} J} = 1.43*10^{16} ev/kg

           An Average american weighs 88.7 kg

      The total energy received is mathematically evaluated as

        1 kg ------> 1.423*10^{16}ev \\88.7kg  --------> x

Cross-multiplying and making x the subject

           x = 88.7 * 1.423*10^{16} eV

              x = 126.2*10^{16}eV

Therefore the total  energy  deposited is x = 126.2*10^{16}eV

The approximate number of decays  this represent  is mathematically evaluated as

            N = \frac{x}{S}

Where n is the approximate number of decay

   Substituting values

                             N = \frac{126 .2*10^{16}}{5.49*10^6}  

                                  N= 23*10^{10}  

                     

             

7 0
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