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3 years ago

(answer only if you know the answer or I'll report) Help me please solve it w steps

Physics

1 answer:

Murrr4er [49]3 years ago

5 0

X component of force Fx=Fcos45=50×cos×45

Y component of force Fy=Fsin45=50×sin×45

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Suppose you have two chains available to suspend an object in the air. Let’s also say that you can arrange the suspension howeve

Liono4ka [1.6K]

<h2>your answer is going to be image 1 that one looks the most decent </h2>

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3 years ago

Read 2 more answers

Describe the effects of energy in your school and community

erastova [34]

Energy keeps our school running properly. Without energy computers, smart-boards, printers, and our lights would not work.

The world runs on energy.

5 0

3 years ago

The angular momentum of a flywheel having a rotational inertia of 0.200 kg · m2 about its central axis decreases from 3.80 to 0.

Bingel [31]

Answer:

14.3065 rad

-36.777 J

-28.29 W

Explanation:

$L_f$ = Final angular momentum = 0.6 kgm²/s

$L_i$ = Initial angular momentum = 3 kgm²/s

I = Moment of inertia = 0.2 kgm²

Torque is given by

$\tau=\dfrac{L_f-L_i}{t}\\\Rightarrow \tau=\frac{0.6-3.8}{1.3}\\\Rightarrow \tau=-2.46\ Nm$

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2$

Initial angular speed is given by

$\omega_i=\dfrac{L_i}{I}$

Angular acceleration is given by

$\alpha=\dfrac{\tau}{I}$

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=\dfrac{L_it+\dfrac{1}{2}\tau t^2}{I}\\\Rightarrow \theta=\dfrac{3.8\times 1.3+\dfrac{1}{2}\times -2.46\times 1.3^2}{0.2}\\\Rightarrow \theta=14.3065\ rad$

The angle is 14.3065 rad

Work done is given by

$W=\tau \theta\\\Rightarrow W=-2.46\times 14.95\\\Rightarrow W=-36.777\ J$

The work done on the wheel is -36.777 J

Power is given by

$P=\dfrac{W}{t}\\\Rightarrow P=\dfrac{-36.777}{1.3}\\\Rightarrow P=-28.29\ W$

The power is -28.29 W

6 0

3 years ago

What is the mass of a dog running at a speed of 5 m/s and a momentum of 120.5 kgm/s?

viktelen [127]

Given:

Momentum of the dog (p) = 120.5 kg m/s

Speed of the dog (v) = 5 m/s

To Find:

Mass of the dog (m)

Concept/Theory:

$\underline{\underline{ \bf{\Large{Momentum}}}}$

It is defined as the quantity of motion contained in a body.
It is measured as the product of mass of the body and it's speed.
It is represented by p.
It's SI unit is kg m/s
Mathematical Representation/Equation of Momentum: $\boxed{ \bf{p = mv}}$

Answer:

By using equation of momentum, we get:

$\rm \longrightarrow m = \dfrac{p}{v} \\ \\ \rm \longrightarrow m = \dfrac{120.5}{5} \\ \\ \rm \longrightarrow m = 24.1 \: kg$

$\therefore$ Mass of the dog (m) = 24.1 kg

6 0

3 years ago

Calculate the minimum amount of energy, in joules, required to completely melt 145 g of silver initially at 22.0°C. The melting

Tcecarenko [31]

Answer:

47391.8 J

Explanation:

Q = m c Δt

For melting, Δt = (962-22)°C

Heat required to attain melting point = 145 x 10 ⁻³ x 236 x 940 =

= 32166.8 J

Heat required to melt at melting point = m L , L is latent heat of fusion.

= 145 x 10⁻³ x 105 x 10³ = 15225 J

Total energy required = 47391.8 J

6 0

4 years ago

(answer only if you know the answer or I'll report) Help me please solve it w steps​

(answer only if you know the answer or I'll report) Help me please solve it w steps