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Marizza181 [45]
3 years ago
10

What is the range of the function?

Mathematics
1 answer:
maw [93]3 years ago
3 0
{3,9,12}

the question is asking for the range, which are the y values
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Norman is a sunflower farmer. His farm is in the shape of a parallelogram with a height measuring 3 kilometers and a base measur
Rom4ik [11]
It neve mentions how much of his farm he uses, but assuming he uses all of it
area=base times height
given
base=4.2
height=3
area=4.2 times 3
area=12.6 square kilometers

answer is 12.6 km²
5 0
2 years ago
Estimate. Them multiply. Use your estimate to check your answer. For 18×8
frez [133]

Answer:

120

Step-by-step explanation:

18x8 is 124 but if you estimate then it is 120 bc 4 or less let it rest 5 or more add one more.

7 0
3 years ago
U/v * 5 where u = 4 and v = 6
Ann [662]
4 divided by 6 times 5 equals 3.333
7 0
2 years ago
Write the equation in standard form for the circle with radius 9 centered at the origin.
amid [387]
The standard form of the equation of a circle of radius r, with (assuming centre h, k) is given as:

(X-h)^2 + (y-k)^2 = r^2

As we are required to write an equation in standard form for the circle with radius 9 centred at the origin.
Centre(h,k)=(0,0), r=9

Substituting these values into the standard form of the equation of a circle given above:

(X-0)^2 + (y-0)^2 = 9^2
X^2 + y^2 =81

The standard form is x^2 + y^2 =81

I’m pretty sure this is right
8 0
2 years ago
Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent
goblinko [34]

Answer:

y(x)=x^2+5x

Step-by-step explanation:

Given: y'=\sqrt{4y+25}

Initial value: y(1)=6

Let y'=\dfrac{dy}{dx}

\dfrac{dy}{dx}=\sqrt{4y+25}

Variable separable

\dfrac{dy}{\sqrt{4y+25}}=dx

Integrate both sides

\int \dfrac{dy}{\sqrt{4y+25}}=\int dx

\sqrt{4y+25}=2x+C

Initial condition, y(1)=6

\sqrt{4\cdot 6+25}=2\cdot 1+C

C=5

Put C into equation

Solution:

\sqrt{4y+25}=2x+5

or

4y+25=(2x+5)^2

y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}

y(x)=x^2+5x

Hence, The solution is y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4} or y(x)=x^2+5x

4 0
3 years ago
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