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2 years ago

What number is 30% of 150

Mathematics

2 answers:

mrs_skeptik [129]2 years ago

8 0

Find 30% of 150. To do this, mult. 150 by 0.30. Result: 45.

vova2212 [387]2 years ago

6 0

$\displaystyle 30\% \ of \ 150 = \\ \\ \frac{30}{10\not0} \cdot 15\not0= \\ \\\\ \frac{30}{10} \cdot 15= \\ \\ \\\frac{450}{10} =45$

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5 less than a number is equivalent to 1 more than three times the number. the number is

lutik1710 [3]

Answer:

x = -1

Step-by-step explanation:

5 less than a number is equivalent to 1 more than three times the number

number = x

x - 5 = 3x + 1

now im going to get the numbers and variable on different sides

x - 5 + 5 = x

3x + 1 - 3x = 1

x + 3x = 4x

1 - 5 = -4

4x = -4

lastly im going to divide each side by 4

4x / 4 = x

-4 / 4 = -1

x = -1

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3 years ago

Round 41.805 to the nearest whole number

aleksandr82 [10.1K]

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3 years ago

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It's a lovely day. It's about 75 degrees - finally shorts weather! - and I can't wait to take a long walk. I leave from my front

maw [93]

Answer:

You'll be back at your friends house

Step-by-step explanation:

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And he traveled 3 blocks each time. its sort if like a square.

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2 years ago

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valentinak56 [21]

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10. Two lighthouses are located on a north-south line.

Kamila [148]

The question is an illustration of bearing (i.e. angles) and distance (i.e. lengths)

The distance between both lighthouses is 5783.96 m

I've added an attachment that represents the scenario.

From the attachment, we have:

$\mathbf{\angle A = 180^o - 120^o\ 43'}$

Convert to degrees

$\mathbf{\angle A = 180^o - (120^o +\frac{43}{60}^o)}$

$\mathbf{\angle A = 180^o - (120^o +0.717^o)}$

$\mathbf{\angle A = 180^o - (120.717^o)}$

$\mathbf{\angle A = 59.283^o}$

$\mathbf{\angle B = 39^o43'}$

Convert to degrees

$\mathbf{\angle B = 39^o + \frac{43}{60}^o}$

$\mathbf{\angle B = 39^o + 0.717^o}$

$\mathbf{\angle B = 39.717^o}$

So, the measure of angle S is:

$\mathbf{\angle S = 180 - \angle A - \angle B}$ ---- Sum of angles in a triangle

$\mathbf{\angle S = 180 - 59.283 - 39.717}$

$\mathbf{\angle S = 81}$

The required distance is distance AB

This is calculated using the following sine formula:

$\mathbf{\frac{AB}{\sin(S)} = \frac{AS}{\sin(B)} }$

Where:

$\mathbf{AS = 3742}$

So, we have:

$\mathbf{\frac{AB}{\sin(81)} = \frac{3742}{\sin(39.717)}}$

Make AB the subject

$\mathbf{AB= \frac{3742}{\sin(39.717)} \times \sin(81)}$

$\mathbf{AB= 5783.96}$

Hence, the distance between both lighthouses is 5783.96 m

Read more about bearing and distance at:

brainly.com/question/19017345

5 0

1 year ago