Question

A dart is thrown at the board shown. It hits the board at a random point. Find the probability that it will land in the unshaded region. Round to the nearest percent.
75%


48%


67%


33%

Answer 1

Answer:

The probability that it will land in the unshaded region in the nearest percent is:

                                       67%

Step-by-step explanation:

We know that a full circle covers a angle of 360° or 2π radians.

The angle that is covered in the unshaded region is: 240°

Hence, the probability is calculated as the ratio of the number of favorable outcome to the total number of outcomes.

The probability in percentage that the dart will land in the unshaded region is:

Ratio of the angle of unshaded region to the angle of the total circle.

$Probability=\dfrac{240}{360}\times 100\\\\\\Probability=66.6667\%$

        Hence, to the nearest percent the probability is:

                       67%

Answer 2

A circle is 1 revolution or 360 degrees. So, the probability that a dart will land in the unshaded region is 

     $P=\frac{240}{360}=67\%$

The answer is 67%.